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Ostrovityanka [42]
2 years ago
11

Why is the first one (A) correct?

Chemistry
1 answer:
skelet666 [1.2K]2 years ago
6 0

Answer: yes it is correct

Explanation: the higher it is the cooler.

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Un gas ocupa 24,6 litros a 27°C y 10 moles, que presión posee. R=0.082
Anastasy [175]

Answer:

P=10 atm

Explanation:

Hola,

En este caso, usando la ecuación del gas ideal, podemos calcular facilmente la presión a partir de:

PV=nRT

Por lo que despejando para la presión obtenemos:

P=\frac{nRT}{V}

Así, calculamos:

P=\frac{10mol*0.082\frac{atm*L}{mol*K}*(27+273)K}{24.6L} \\\\P=10 atm

¡Saludos!

7 0
3 years ago
A calorimeter was used to measure the heat change when an ionic compound dissolves in water. The final mass of the contents of t
Lemur [1.5K]
The answer
the main formula is given by
Q=mSDT
 where m= mass
             s= specific heat
             DT= <span>change in temperature

so  Q =  50.89 x 1.8x 4.11 = 376.48</span>


6 0
3 years ago
The density of octane is 0.700 g/cm3.  What is the mass of one liter of octane?
Gelneren [198K]

Answer:

m = 700 g

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

Density of octane = 0.700 g/cm³

Volume = 1 L

Mass = ?

Formula:

D=m/v

D= density

m=mass

V=volume

First of all we will convert the volume in cm³ because density is given in g/cm³ unit.

1 L = 1000 cm³

Now we will put the values in formula:

d= m/v

m = v × d

m = 1000 cm³ × 0.700 g/cm³

m = 700 g

5 0
3 years ago
Which of the following is NOT an example of potential energy?
Diano4ka-milaya [45]

Answer:

A. car moving down the highway

Explanation:

Potential energy is when the energy is being held in, as in, it is very still, and not moving.

When a car is moving down a highway, it is releasing kinetic energy, instead of potential.

4 0
3 years ago
How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?
miss Akunina [59]
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
In the givens you have:
M1 = 2M
V1 is the unknown
M2 = 0.4M
V2 = 100 ml

</span>plug in the givens in the above equation:
<span>2 x V1 = 0.4 x 100 
</span>therefore:
V1 = 20 ml

Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

7 0
3 years ago
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