Two blocks are on a horizontal frictionless surface. Block a is moving with an initial velocity
1 answer:
The final velocity of the block A will be 2.5 m/sec. The principal of the momentum conversation is used in the given problem.
<h3>What is the law of conservation of momentum?</h3>According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and m₂ will be u₁=5 and u₂=0 m/s respectively,
According to the law of conservation of momentum
Momentum before collision =Momentum after collision
m₁u₁+m₂u₂=(m₁+m₂)v
M×5+3M×0=[M+3M]v
The final velocity is found as;
V=51.25 m/s
The velocity of block A is found as;
Hence, the final velocity of the block A will be 2.5 m/sec.
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Answer:
v= 14.85 m/s
Explanation:
- When at the bottom of the dip, the only force that keeps the car in the circular trajectory, is the centripetal force.
- This force is not a new force, is just the net force aiming to the center of the circle.
- In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward.
- So, we can write the following expression:
- It can be showed that the centripetal force is related to the speed by the following expression:
- The normal force, it is called the apparent weight, because it would be the weight as measured by a scale.
- Replacing (2) in (1), and solving for Fn, we get:
- Now, we need to find the value of v that makes Fn, exactly 15% more than the weight m*g, so we can write the following equation:
- Replacing Fg by its value, simplifying, and solving for v, we get: