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ElenaW [278]
3 years ago
11

A basketball is tossed up into the air, falls freely, and bounces from the wooden floor. From the moment after the player releas

es it until the ball reaches the top of its bounce, what is the smallest system for which momentum is conserved?'
Physics
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

Tha ball- earth/floor system.

Explanation:

The force acting on the ball is the force of gravity when ignoring air resistance. At the moment the player releases the ball, until it reaches the top of its bounce, the small system for which the momentum is conserved is the ball- floor system. The balls exerts and equal and opposite force on the floor. <u>Here the ball hits the floor, because in any collision the momentum is conserved. Moment of the ball -floor system is conserved</u>. Mutual gravitation bring the ball and floor together in one system. As the ball moves downwards, the earth moves upwards, although with an acceleration on the order of 1025 times smaller than that of the ball. The two objects meet, rebound and separate.

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First I’ll show you this standard derivation using conservation of energy:
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in the primitive yo-yo apparatus (figure 1), you replace the solid cylinder with a hollow cylinder of mass m , outer radius r ,
kirza4 [7]

The magnitude of the downward acceleration of the hollow cylinder is 6m/s^2.

Z = I α

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T.R = 1/2M 5R^{2}/4 α

T = 5Ma/8

Mg - T = Ma

Mg -  5Ma/8 =  Ma

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The rate at which an object's velocity with respect to time changes is called its acceleration. The direction of the net force imposed on an item determines its acceleration in relation to that force. According to Newton's Second Law, the magnitude of an object's acceleration is the result of two factors working together

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2 years ago
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To solve this problem we will use the basic concept given by the Volume of a sphere with which the atom approaches. The fraction in percentage terms would be given by the division of the total volume of the nucleus by that of the volume of the atom, that is,

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Therefore the percent of the atom's volume is occupied by mass is 7.51*10^{-11}\%

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