The absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.
<h3>Absence of external force on the outer space</h3>
The outer space is almost an absolute vacuum, because it's nearly empty. There is no matter such as air in the outer space that will provide an external force needed to change the velocity of the piece of rock.
From Newton's first law of motion, an object in a state of rest or uniform motion in a straight line, will continue in that state unless it is acted upon by an external force.
Thus, the absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.
Learn more about outer space here: brainly.com/question/24701339
Are you familiar with any basic calculus? If so, we can just look at this derivative and see what's happening with our units here..
Here it shows that acceleration is the derivative of velocity with respect to time. In other words, we can say that:
We can read that equation as: "acceleration is the change of velocity divided by the change in time (aka the time interval)."
If you're not familiar with calculus, we can use a simple equation of motion:
where:
vf = final velocity
vi = initial velocity
a = acceleration
t = observed time interval
We can rearrange this equation to find:
This is the same exact thing we wrote before!
Pressure is defined as the force per unit area on a body.
When a plane travels 395,000 meters in 9,000 seconds its speed is 395,000 ÷ 9000 = 43.888888 (the 8 repeats) meters per second.
Answer:
892 Hz or 842 Hz
Explanation:
Given
The frequency of first guitar is 867 Hz
Beat is produced for every 0·04 s
∴ Beat has a time period of 0·04 s
<h3>Beat frequency is defined as the inverse of the time period of the beat </h3>
Beat frequency = 1 ÷ (Time period) = 1 ÷ 0·04 = 25 Hz
Let the frequency of the second guitar be f Hz
<h3>Beat frequency is defined as the absolute difference between the two frequencies</h3>
∴ Beat frequency = (867 - f) or (f - 867)
First case
25 = 867 - f ⇒ f = 842 Hz
Second case
25 = f - 867 ⇒ f = 892 Hz
∴ Possible frequencies of second guitar could be 892 Hz or 842 Hz
