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vaieri [72.5K]
2 years ago
9

Letícia leaves the grocery store and walks 150. 0 m to the parking lot. Then, she turns 90° to the right and walks an additional

70. 0 m to her car. What is the magnitude of the displacement of her car from the grocery store exit? round your answer to the nearest tenth.
Physics
2 answers:
slava [35]2 years ago
8 0

d = displacement

a triangle, displacement = hypotenuse = phytagoras

\tt d=\sqrt{70^2+150^2}=165.5~m

Eduardwww [97]2 years ago
6 0
165.5 m is the answer
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When might it be harder to stop a vehicle moving at 30 km/h than one moving at 60 km/h?
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when the momentum of the vehicle moving at 30 km/h is higher than the one from the vehicle moving at 60 km/h

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1 year ago
A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The
Ber [7]

Answer:

1. v=14.2259\ m.s^{-1}

2. F_T=25.8924\ N

3. \lambda=29.6373\ m

Explanation:

Given:

  • mass of slinky, m=0.87\ kg
  • length of slinky, L=6.8\ m
  • amplitude of wave pulse, A=0.23\ m
  • time taken by the wave pulse to travel down the length, t=0.478\ s
  • frequency of wave pulse, f=0.48\ Hz=0.48\ s^{-1}

1.

\rm Speed\ of\ wave\ pulse=Length\ of\ slinky\div time\ taken\ by\ the\ wave\ to\ travel

v=\frac{6.8}{0.478}

v=14.2259\ m.s^{-1}

2.

<em>Now, we find the linear mass density of the slinky.</em>

\mu=\frac{m}{L}

\mu=\frac{0.87}{6.8}\ kg.m^{-1}

We have the relation involving the tension force as:

v=\sqrt{\frac{F_T}{\mu} }

14.2259=\sqrt{\frac{F_T}{\frac{0.87}{6.8}} }

202.3774=F_T\times \frac{6.8}{0.87}

F_T=25.8924\ N

3.

We have the relation for wavelength as:

\lambda=\frac{v}{f}

\lambda=\frac{14.2259}{0.48}

\lambda=29.6373\ m

8 0
2 years ago
An object of mass 25kg is falling from the height h=10 m. calculate
r-ruslan [8.4K]

Answer:

a=2500J,b=1000K,c=1000J,d=14.142m/s

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potential energy=mgh

p.e=25×10×10=2500J

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b).mgh=25×10×4=1000J

c). V²=U²+2gh

V²=0+2×10×4

V²=80

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d). From my first paragraph V²=200

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