True or false Water is a solute in moist air
2 answers:
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The tension in the rope when the gymnast climbs it at constant speed is 641.9 N.
Given:
Mass of gymnast, m = 65.5 kg
The speed 'v' of gymnast is constant
Solution:
Consider the free-body diagram of the system as shown below.
Balancing forces along the vertical axis we get:
ΣFy = 0
Thus, we get:
F = ma - (1)
where, m is mass of gymnast
a is acceleration of gymnast (a = 0m/s², as the speed is constant)
Also,
F = T - mg -(2)
where, T is tension in the rope
g is acceleration due to gravity
Equating (1) & (2), we get:
ma = T - mg
Re-arranging the equation, we get:
T = m(a+g)
Applying values in above equation we get:
T = (65.5 kg)(0 m/s²+9.8 m/s²)
T = 641.9 N
Therefore, the tension in the rope when the gymnast climbs it at constant speed is 641.9 N.
Learn more about tension here:
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Answer:
a)V = 25.1 m/s
b)V = 4.226 m/s
Explanation:
Given that
x(t)=A t + B t²
A = -4.3 m/s
B = 4.9 m/s²
x(t)= - 4.3 t +4.9 t²
The velocity of the particle is given as
V=-4.3 + 4.9 x 2 t
V= - 4.3 + 9.8 t m/s
Velocity at point t= 3 s
V= - 4. 3 + 9.8 x 3 m/s
V= - 4.3 + 29 .4 m/s
V = 25.1 m/s
At origin :
x= 0 m
0 = - 4.3 t +4.9 t²
0 = - 4.3 + 4.9 t
t=0.87 s
The velocity at t= 0.87 s
V= - 4.3 + 9.8 t m/s
V= - 4. 3 + 9.8 x 0.87 m/s
V= - 4.3 + 8.526 m/s
V = 4.226 m/s
a)V = 25.1 m/s
b)V = 4.226 m/s