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3 years ago

True or false Water is a solute in moist air

Physics

2 answers:

Advocard [28]3 years ago

8 0

Answer:

True

Explanation:

Oxana [17]3 years ago

3 0

Answer:

its true water is a solute in moist air

Explanation:

i hope i helped

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What are the benefits and harms of protists? WILL GIVE BRAINLIEST FOR THE PERFECT ANSWER

alina1380 [7]

Answer:

<em>Well, Many protists are harmful to humans, other animals and plants because they cause diseases and crop failures. However, some protists are actually beneficial to other creatures and are used by humans for various purposes. Plant-like protists produce almost one-half of the oxygen on the planet through photosynthesis. Other protists decompose and recycle nutrients that humans need to live. For example, medicines made from protists are used in treatment of high blood pressure, digestion problems, ulcers, and arthritis. Hope That Helps!</em>

<em>From ~Itsbrazts~. Have a Great Day!</em>

6 0

3 years ago

Read 2 more answers

A truck driver is going down a one way street the wrong way, and passes at least ten cops. Why is he not caught?

garik1379 [7]

I think because there is only one way to go

6 0

3 years ago

A wave has a wavelength of 125 meters is moving at a speed of 20 m/s. What is it’s frequency?

Ann [662]

Answer: 0.16Hz

Explanation:

Given that:

wavelength (λ) = 125 meters

speed (V) = 20 m/s

frequency (F) = ?

Recall that frequency is the number of cycles the wave complete in one second. And its value depends on the wavelength and speed of the wave.

So, apply the formula V = F λ

Make F the subject formula

F = V / λ

F = 20 m/s / 125 meters

F = 0.16 Hz

Thus, the frequency of the wave is 0.16 Hertz.

4 0

3 years ago

Scientists want to place a 3400.0 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2480.0

BaLLatris [955]

Answer:

Part a)

$r = 6.96 \times 10^6 m$

Part b)

$F_g = 3.004 \times 10^3 N$

Part c)

$a = 0.88 m/s^2$

Part d)

$v = \frac{2480}{2} = 1240 m/s$

Explanation:

Part a)

As we know that the orbital speed of the satellite is given as

$v = 2480 m/s$

now we will have

$v = \sqrt{\frac{GM_{mars}}{r}}$

now we have

$M_{mars} = 6.4191 \times 10^{23} kg$

$R_{mars} = 3.397 \times 10^6 m$

now we have

$2480 = \sqrt{\frac{(6.67 \times 10^{-11})(6.4191 \times 10^{23})}{r}}$

$r = 6.96 \times 10^6 m$

Part b)

Here force between mars and satellite is the gravitational attraction force which is given as

$F_g = \frac{GM_{mars} m}{r^2}$

$F_g = \frac{(6.67\times 10^{-11})(6.4191 \times 10^{23})(3400)}{(6.96\times 10^6)^2}$

$F_g = 3.004 \times 10^3 N$

Part c)

Acceleration of satellite is the ratio of gravitational force and mass of the satellite

$a = \frac{F_g}{m}$

$a = \frac{3004}{3400}$

$a = 0.88 m/s^2$

Part d)

As we know by III law of kepler

$\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}$

here we know that T2 = 8 T1

$(\frac{1}{8})^2= \frac{r_1^3}{r_2^3}$

$\frac{r_1}{r_2} = (\frac{1}{2})^2$

so we have

$r_2 = 4r_1$

as we know that speed is given as

$v = \sqrt{\frac{GM}{r}}$

so we can say since radius is orbit becomes 4 times so the orbital speed must be half

$v = \frac{2480}{2} = 1240 m/s$

7 0

4 years ago

A receiver catches a football on the 50.0 yard line and is tackled 5.42 seconds later on the 12 yard line. What

tester [92]

Answer:

7.01yard/sec

Explanation:

Given parameters:

Initial position = 50yard

Final position = 12yard

Time = 5.42s

Unknown:

Average speed of runner = ?

Solution:

To solve this problem;

Speed = $\frac{distance}{time}$

Distance covered = Initial position - final position = 50 - 12 = 38yards

So;

Speed = $\frac{38}{5.42}$ = 7.01yard/sec

5 0

3 years ago