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Karolina [17]
3 years ago
8

Describe a real-world example of the law of conservation of momentum.

Physics
1 answer:
mario62 [17]3 years ago
4 0
Imagine a car crash. A car coming at a high speed has a head on collision with a car at rest. When the car makes impact, it will move the other car with it at a slower speed then it was travelling at. In this case, the velocity decreased since the car slowed down, but the mass increased since there are now two cars moving. Momentum was conserved because the change in mass accounts for the loss of velocity.
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HELP PLS WHAT IS Y COMPONENT
jeka94

Answer:

11.5

Explanation:

you do 12(sin 73.3) because its on the y you do sin

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3 years ago
What must be the distance between point charge 91 = 20 MC and point charge 02 -45,0 AC for the electrostatic force between them
Fynjy0 [20]

Answer:

Explanation:

Q₁ = 20 X 10⁻⁶ C

Q₂ = -45 X 10⁻⁶ C

d is required distance.

F = Force between the = 7 N

F = k x Q₁ X Q₂ / d²

d² = k x Q₁ X Q₂ / F = 20 X 45 X 10⁻¹² X 9 X 10⁹  /7

=1.157

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4 years ago
The diagram shows light passing through and opening and forming bonds. Which two order bands are the dimmest?
Oxana [17]
I think its option d
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7 0
4 years ago
Read 2 more answers
What is the net force on this object: F norm = 20N F frict = 14N F app = 22N F grav = 20N?
viva [34]

Answer:

8N i believe

Explanation:

4 0
3 years ago
Read 2 more answers
5. A 1.15-kg grinding wheel 22.0 cm in diameter is spinning counterclockwise at a rate of 20.0 revolutions per second. When the
suter [353]

Answer:

a) -1.57 rad/s²

b) 800 revolutions

Explanation:

a)In here you can use the equations of velocity as if it were a linear movement. In this case:

wf = wo + at

wo is the innitial angular velocity, that we can get this value using the fact that a revolution is 2π so:

wo = 20 * 2π = 125.66 rad/s

We have the time of 80 seconds, and the final angular speed is zero, because it's going to a rest so:

0 = 125.66 + 80a

a = -125.66 / 80

a = -1.57 rad/s²

b) In this part, we will use the following expression:

Ф = Фo + wo*t + 1/2 at²

But as this it's coming to rest then:

Ф = 1/2at²

solving we have:

Ф = 0.5 * (-1.57)*(80)²

Ф = 5,024 rad

Ф = 5024 / 2π

Ф = 800 revolutions

3 0
4 years ago
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