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3 years ago

Describe a real-world example of the law of conservation of momentum.

1 answer:

4 0

Imagine a car crash. A car coming at a high speed has a head on collision with a car at rest. When the car makes impact, it will move the other car with it at a slower speed then it was travelling at. In this case, the velocity decreased since the car slowed down, but the mass increased since there are now two cars moving. Momentum was conserved because the change in mass accounts for the loss of velocity.

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seraphim [82]

Magnitude and direction

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3 years ago

The knights of labor do not believe in arbitration but believed in strikes? true or false

Rus_ich [418]

Answer - The given statement is false.

Explanation-

The members of knight of labour were opposing strikes and had a belief or boycott or arbitration.

A secret society was formed in 1869 by the tailors in Philadelphia and named Knights of labour. This union Organisation was formed to to get rights over equal pay if work is equal, abolish child labour, Work time of 8 hours and some graduated income tax reforms. This union was vertically organized.

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3 years ago

The horizontal beam in Fig. E11.14 weighs 190 N, and its center of gravity is at its center. Find (a) the tension in the cable a

grandymaker [24]

Answer:

(a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

Explanation:

Given that,

Weight of beam= 190 N

Here, The center of gravity is at its center

According to figure,

The angle is

$\sin\theta=\dfrac{3}{5}$

The horizontal component is

$T_{x}=T\cos\theta$

The vertical component is

$T_{y}=T\sin\theta$

(a). We need to calculate the tension in the cable

Using formula of net torque acting on the pivot

$\sum\tau=F_{b}\times r+F_{w}\times r'-T\sin \theta\times r'$

Put the value into the formula

$0=190\times2+300\times 4-T\sin\theta\times 4$

$T\sin\theta\times 4=380+1200$

$T=\dfrac{1580\times5}{3\times 4}$

$T=658.33\ N$

(b). We need to calculate the horizontal components of the force exerted on the beam at the wall

Using formula of horizontal component

$F_{x}=T\cos\theta$

Put the value into the formula

$F_{x}=658.33\times\dfrac{4}{5}$

$F_{x}=526.66\ N$

(c). We need to calculate the vertical components of the force exerted on the beam at the wall

Using formula of vertical component

$F_{y}=F_{b}+F_{w}-T\sin\theta$

Put the value into the formula

$F_{y}=190+300-658.33\times\dfrac{3}{5}$

$F_{y}=95.002\ N$

Hence, (a). The tension in the cable is 658.33 N.

(b). The horizontal components of the force exerted on the beam at the wall is 526.66 N.

(c). The vertical components of the force exerted on the beam at the wall is 95.002 N.

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3 years ago

Any push or pull on an object is Question 5 options: Acceleration Velocity Force Inertia

Kobotan [32]

This would be force. Acceleration is increasing the speed in an object and velocity is how fast an object is going. Also, inertia basically says that an object will stay at rest or in motion unless an outside force acts on it. So, for example, a ball will stay in the air unless gravity acts on it and pulls it down. By definition, force is any action, unopposed (or by itself without any other forces that would do the opposite) will change the motion of an object, so this definitely makes the most sense for the question. Hope this helps!

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It is the branch of science, in which we study different phenomena of atmosphere including climate and weather.

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