Answer:
Solution
dT = K * b
K (H2O) = 1.86 0C
b(C2H6O2) = dT/ K = 33.2 / 1.86 = 17.85(mol/kg)
b(C2H6O2)= n (C2H6O2) / m (H2O)
m (H2O) = V * = 12.2 * 1 = 12.2 (kg)
n (C2H6O2) = b (C2H6O2) * m (H2O) = 17.85 * 12.2 = 217.77 (mol)
n (C2H6O2) = m / M;
m (C2H6O2) = n * M = 217.77 * (12*2 + 1*6 + 16 *2) = 13501.74 (g) = 13.5 (kg)
V (C2H6O2) = m / = 13.5 / 1.11 = 12.16 (L)
Answer V (C2H6O2) = 12.16 L
~The picture below shall help :)
-Hope this helped ^_^
The answer is 0.25 M
Use the equation C1V1=C2V2
(.5)(100)=x(200)
x=0.25
What is the increment of change in a series of straight-chain alkanes?
CH
CH3
CH4
CH2
Answer:
CH2