Answer:
a) Work done on the box by pushing force P : W= + 1088 J
b) Work done on the box by the weight(W) of the box: W=0
c) Work done on the box by normal force N : W=0
d) Work done on the box by the frictional force f :W = -620.92 J
Explanation:
Work is defined as the Scalar product of force F by the distance the body travels due to this force.
W= F*d*cosα Formula ( 1)
Where:
W: Work done on the body by the force (J)
d : distance the body travels (m)
α : angle formed between force and displacement (°)
The work is positive (W+) if the force has the same direction of movement of the object. (because α=0°, cos 0°=1)
The work is negative (W-) if the force has the opposite direction of the movement of the object.
(because α=180°, cos180°=-1)
The component of the force that performs work must be parallel to the displacement (because α=0°, cos 0°=1)
Perpendicular forces to displacement do not perform work (because α=90°,cos 90°=0)
Forces that act on the box:
Pushing force: P = 170 N
Weight :W= m*g= 45 kg * 9.8 m/s²= 441 N
Normal force : N
Frictional force : f
We apply Newton's second law to calculate N
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
∑Fy = m*ay , ay=0
N-W = 0
N=W = 441 N
We apply the following formula to calculate f:
f= μk*N Formula (2)
Where:
Friction force : f
μk: coefficient of kinetic friction
N : Normal force (N)
Data: μk= 0.22 , N= 441 N
We replace data in the formula (2)
f= 0.22*441
f= 97.02 N
Calculating the work done on the box by each of the four forces that act on the box
We apply the formula (1) to calculate the work
a) Work done on the box by pushing force P
P= 170 , d=6.4 m , α= 0°
W= P*d*cosα = 170N*6.4m*cos0° = 1088 N *m
W= 1088 J
b) Work done on the box by the weight(W) of the box
W= 441 N , d=6.4 m , α= 90°
W= 441N *6.4m*cos90°=0
W=0
c) Work done on the box by normal force N
N= 441 N , d=6.4 m , α= 90°
W= 441N *6.4m*cos90°=0
W=0
d) Work done on the box by the frictional force f
f= 97.02 N , d=6.4 m , α= 180°
W= 441N *6.4m*cos 180°
W = -620.92 N
