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garik1379 [7]
3 years ago
9

To be able to solve problems involving force, moment, velocity, and time by applying the principle of impulse and momentum to ri

gid bodies. The principle of impulse and momentum states that the sum of all impulses created by the external forces and moments that act on a rigid body during a time interval is equal to the change in the linear and angular momenta of the body during that time interval. In other words, impulse is the change in momentum. The greater the impulse exerted on a body, the greater the body’s change in momentum. For example, baseball batters swing hard to maximize the impact force and follow through to maximize the impact time. This principle holds true for both linear and angular impulse and momentum. For a rigid-body’s planar motion, the equations for the linear impulse and momentum in the x–y plane are given by m(vGx)1+∑∫t2t1Fxdt=m(vGx)2 m(vGy)1+∑∫t2t1Fydt=m(vGy)2 Similarly, the equation for the principle of angular impulse and momentum about the z axis, which passes through the rigid-body’s mass center G, is given by IGω1+∑∫t2t1MGdt=IGω2

Engineering
2 answers:
coldgirl [10]3 years ago
3 0

Answer:

see explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

The attached files has the solved problem.

dalvyx [7]3 years ago
3 0

Answer: 3.33T rad/s

Explanation:

here is a step by step explanation for the problem.

we have that the Moment of inertia of the pulley Ia = 0.225 Kg-m³

                                           Radius of the pulley r = 0.15m

                                           Mass of the pulley m = 20 Kg

we know that the torque acting on the pulley (Tr) = Iα

where α = Tr/ I

here, T is the tension of the cord,

also α is the angular acceleration ,

also, I is the moment of inertia and r is  the radius.

from 2nd rotational kinematics law;

ω₂ = ω₁ + αt .................. (1)

given that ω₂ and ω₁ is the final and inertia angular velocity, t is the time.

note: initial velocity (ω₁) is zero since system is at rest.

now from the expression in (1)

ω₂ = ω₁ + αt

= (0) + (Tr/I)t

ω₂ = (T(0.15) / 0.225 )*(5) = 3.33T rad/s

from this we can say that the angular velocity of the pulley is 3.33T rad/s at t = 5sec

cheers i hope this helps!!!!

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A 1000-turn coil of wire 1.0 cm in diameter is in a magnetic field that increases from 0.10 T to 0.30 T in 10 ms. The axis of th
ddd [48]

emf generated by the coil is 1.57 V

Explanation:

Given details-

Number of turns of wire- 1000 turns

The diameter of the wire coil- 1 cm

Magnetic field (Initial)= 0.10 T

Magnetic Field (Final)=0.30 T

Time=10 ms

The orientation of the axis of the coil= parallel to the field.

We know that EMF of the coil is mathematically represented as –

E=N(ΔФ/Δt)

Where E= emf generated

ΔФ= change inmagnetic flux

Δt= change in time

N= no of turns*area of the coil

Substituting the values of the above variables

=1000*3.14*0.5*10-4

=.0785

E=0.0785(.2/10*10-3)

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4 0
3 years ago
Write a Nios II assembly program that reads binary data from the Slider Switches, SW11-0, on the DE2-115 Simulator, and display
Citrus2011 [14]

Algorithm of the Nios II assembly program.

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  • The data will be  read from the switches in loop.
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  • The program is ended by the user operating the SW1 switch

and

The decimal equivalent on the seven-segment displays HEX3-0 is

  • DE2-115
  • DE2-115_SW11
  • DE2-115_HEX3
  • DE2-115_HEX4
  • DE2-115_HEX5
  • DE2-115_HEX6
  • DE2-115_HEX7

<h3>The  Algorithm and decimal equivalent on the seven-segment displays HEX3-0</h3>

Generally,  the program will be written using a  cpulator simulator in order to attain best result.

We are to

  • Attain data for simulation from the  SW11-0, on the DE2-115 Simulator
  • The data will be  read from the switches in loop.
  • The decimal output is displayed using the seven-segment displays and done using the loop.
  • The program is ended by the user operating the SW1 switch

This will be the Algorithm of the Nios II assembly program .

Hence, the decimal equivalent on the seven-segment displays HEX3-0 is

  • DE2-115
  • DE2-115_SW11
  • DE2-115_HEX3
  • DE2-115_HEX4
  • DE2-115_HEX5
  • DE2-115_HEX6
  • DE2-115_HEX7

For more information on Algorithm

brainly.com/question/11623795

6 0
2 years ago
The Energy Losses Associated with Valves and Fittings: a)- are generally associated with a K factor b)- are generally associated
madam [21]

Answer:

a)Are generally associated with factor.

Explanation:

We know that losses are two types

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2.Minor loss  :Due to change in the direction of flow

As we know that when any hindrance is produced during the flow of fluid then it leads to generate the energy losses.If flow is along uniform diameter pipe then there will not be any loss but if any valve and fitting placed is the path of fluid flow due to this direction of fluid flow changes and  it produce losses in the energy.

Lot' of experimental data tell us that loss in the energy due to valve and fitting are generally associated with K factor.These losses are given as

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8 0
3 years ago
In Lab 7, we worked through a program that displayed the homeless shelter occupancy over time. The same approach can be used for
Bezzdna [24]

Answer:

Explanation:

The python code to generate this is quite simple to run.

i hope you understand everything written here, you can as well try out other problems to understand better.

First to begin, we import the package;

Code:

import pandas as pd

import matplotlib.pyplot as plt

name = input('Enter name of the file: ')

op = input('Enter name of output file: ')

df = pd.read_csv(name)

df['Date'] = pd.to_datetime(df["Date"].apply(str))

plt.plot(df['Date'],df['Absent']/(df['Present']+df['Absent']+df['Released']),label="% Absent")

plt.legend(loc="upper right")

plt.xticks(rotation=20)

plt.savefig(op)

plt.show()

This should generate the data(plot) as seen in the uploaded screenshot.

thanks i hope this helps!!!

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OverLord2011 [107]

Answer:

D

Explanation:

I would say this awnser because its the only one that makes sence to me

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