Answer:
Explanation:
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In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:
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Answer:
Molar Mass of Calcium Carbonate = 100g
given mass = 50g
Number of mole of Calcium Carbonate =50/100 = 0.5 mole
Molarity = mole per litre of volume
Molarity = 0.5 /0.25 = 2mole/litre
Explanation:
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Answer:
x = -3
Explanation:
8(6x + 4) = -112
Divide both sides by 8.
6x + 4 = -14
Subtract 4 from both sides.
6x = -18
Divide both sides by 6.
x = -3
