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1 year ago

Why does fluorine have the highest electronegativity

Chemistry

1 answer:

grandymaker [24]1 year ago

4 0

Answer:

- Fluorine has 5 Electrons in its 2P shell

- Fluorine is so close to ideal Electron Configuration, the Electrons are held very tightly to the Nucleus.

Explanation:

Hopefully this was helpful!

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During lab, you learned about exothermic and endothermic heats of solution. which compounds below could be used for a hot pack?

tatiyna

What are the options? It says select all that apply...

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2 years ago

If you are given the number of molecules in an unidentified chemical compound can you calculate the number of moles in this samp

Sever21 [200]

Yes.
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You can rearrange that formula to find the number of Mols. Hope this helped

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2 years ago

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Is reformed energy nonrenewable or renewable

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Explanation:

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1 year ago

A mixture of 0.682 mol of H2 and 0.440 mol of Br2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 70

ahrayia [7]

Answer: 0.294 mol of $Br_2$ present in the reaction vessel.

Explanation:

Initial moles of $H_2$ = 0.682 mole

Initial moles of $Br_2$ = 0.440 mole

Volume of container = 2.00 L

Initial concentration of $H_2=\frac{moles}{volume}=\frac{0.682moles}{2.00L}=0.341M$

Initial concentration of $Br_2=\frac{moles}{volume}=\frac{0.440moles}{2.00L}=0.220M$

equilibrium concentration of $H_2=\frac{moles}{volume}=\frac{0.536mole}{2.00L}=0.268M$

The given balanced equilibrium reaction is,

$H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)$

Initial conc. 0.341 M 0.220 M 0 M

At eqm. conc. (0.341-x) M (0.220-x) M (2x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[HBr]^2}{[Br_2]\times [H_2]}$

we are given : (0.341-x) = 0.268 M

x= 0.073 M

Thus equilibrium concentration of $Br_2$ = (0.220-x) M = (0.220-0.073) M = 0.147 M

$[Br_2]=\frac{moles}{volume}\\0.147=\frac{xmole}{2.00L}\\\\x=0.294 mole$

Thus there are 0.294 mol of $Br_2$ present in the reaction vessel.

7 0

2 years ago