1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IRINA_888 [86]
3 years ago
13

What is the molarity of 50gram of calcium carbonate is dissolved in 250ML of water​

Chemistry
2 answers:
m_a_m_a [10]3 years ago
7 0

Answer:

Molar Mass of Calcium Carbonate = 100g

given mass = 50g

Number of mole of Calcium Carbonate =50/100 = 0.5 mole

Molarity = mole per litre of volume

Molarity = 0.5 /0.25 = 2mole/litre

Explanation:

hope it helps ......

mark me as brainliest ❤️

lisabon 2012 [21]3 years ago
6 0

Answer:

mass \: of \: solute = 50 g \\ volume \: of \: the \: solution = 250ml \\ molar \: mass \: of \: solute \:  = 100 \frac{g}{mol}  \\ molarity =  \frac{mole}{volume}  \\  =  \frac{ \frac{50}{100} }{250 \times  {10}^{ - 3} }  \\  =  \frac{.5 \times  {10}^{3} }{250}  \\  =  \frac{500}{250}   \\  = 2mol \\ thank \: you

You might be interested in
A solution
Gelneren [198K]
A solution <span>has a uniform composition and is only able to be separated by chemical means.</span>
4 0
2 years ago
Where on the table would a group's<br> ionization energy be the greatest?
Ymorist [56]

Answer:

upper left

Explanation:

it is a trend on the periodic table. Ionization energy increases from left to right(->) I t also increases down to up

5 0
2 years ago
Calculate the pH of a 2.3 10-3M[OH'] solution.
disa [49]

Answer:

11.33

Explanation:

-log(2.3x10^-3) = 2.67

14-2.67

- Hope this helped! Let me know if you need a further explanation.

5 0
3 years ago
A student mixes 33.0 mL of 2.70 M Pb ( NO 3 ) 2 ( aq ) with 20.0 mL of 0.00157 M NaI ( aq ) . How many moles of PbI 2 ( s ) prec
GalinKa [24]

<u>Answer:</u> The moles of precipitate (lead (II) iodide) produced is 1.57\times 10^{-5} moles

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

  • <u>For lead (II) nitrate:</u>

Molarity of lead (II) nitrate solution = 2.70 M

Volume of solution = 33.0 mL = 0.033 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

2.70M=\frac{\text{Moles of lead (II) nitrate}}{0.033L}\\\\\text{Moles of lead (II) nitrate}=(2.70mol/L\times 0.0330L)=0.0891mol

  • <u>For NaI:</u>

Molarity of NaI solution = 0.00157 M

Volume of solution = 20.0 mL = 0.020 L

Putting values in equation 1, we get:

0.00157M=\frac{\text{Moles of NaI}}{0.020L}\\\\\text{Moles of NaI}=(0.00157mol/L\times 0.0200L)=3.14\times 10^{-5}mol

For the given chemical reaction:

Pb(NO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaNO_3(aq.)

By Stoichiometry of the reaction:

2 moles of NaI reacts with 1 mole of lead (II) nitrate

So, 3.14\times 10^{-5} moles of NaI will react with = \frac{1}{2}\times 3.14\times 10^{-5}=1.57\times 10^{-5}mol of lead (II) nitrate

As, given amount of lead (II) nitrate is more than the required amount. So, it is considered as an excess reagent.

Thus, NaI is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 3.14\times 10^{-5} moles of NaI will produce = \frac{1}{2}\times 3.14\times 10^{-5}=1.57\times 10^{-5}moles of lead (II) iodide

Hence, the moles of precipitate (lead (II) iodide) produced is 1.57\times 10^{-5} moles

4 0
2 years ago
A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33
ANEK [815]

Explanation:

The given data is as follows.

     Vapour pressure of pure CCl_{4} = 33.85 Torr

         Temperature = 298 K

      Mole fraction of Br_{2} = 122.36 torr

Therefore, calculate the vapor pressure of Br_{2} as follows.      

     Vapour pressure of Br_{2} = mole fraction of Br_{2} x K of Br_{2}

                                    = 0.050 x 122.36 Torr

                                   = 6.118 Torr

So, vapor pressure of Br_{2} is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

     Vapour pressure of CCl_{4} = mole fraction of CCl_{4} x Pressure of CCl_{4}

                                     = (1 - 0.050) × 33.85 Torr

                                     = 32.1575 Torr

So, vapor pressure of CCl_{4} is 32.1575 Torr  .

Hence, the total pressure will be as follows.

                         = 6.118 Torr + 32.1575 Torr

                         = 38.2755 Torr

Therefore, composition of CCl_{4} = \frac{32.1575 Torr}{38.2755 Torr}

                         = 0.8405

Composition of CCl_{4} is 0.8405 .

And, composition of Br_{2} = \frac{6.118 Torr}{38.2755 Torr}

                                                  = 0.1598

Composition of Br_{2} is 0.1598 .

6 0
3 years ago
Other questions:
  • It is considered a DUI if the driver’s Blood Alcohol Content level is at or above .08.
    12·1 answer
  • Give the nuclear symbol for the isotope of phosphorus for which a=31? enter the nuclear symbol for the isotope (e.g., 42he).
    9·1 answer
  • A drop of gasoline has a mass of 22 mg and a density of 0.754 g/cm3. What is its volume in cubic centimeters?
    8·2 answers
  • Which of the following is an example use of a noble gas?
    11·2 answers
  • PLS HELP ITS URGENT
    15·1 answer
  • Someone please help fast
    14·1 answer
  • Perfume evaporating is it a chemical change or physical change
    10·2 answers
  • How much heat (kJ) is absorbed from water in order for 5.50 moles NH4NO3 to dissolve in water?
    7·1 answer
  • In the compound 5Cr2O3 the 5 represents
    15·2 answers
  • If the male monster has a genotype of Yy, will his ears be pointy or round?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!