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3 years ago

What is the molarity of 50gram of calcium carbonate is dissolved in 250ML of water

Chemistry

2 answers:

m_a_m_a [10]3 years ago

7 0

Answer:

Molar Mass of Calcium Carbonate = 100g

given mass = 50g

Number of mole of Calcium Carbonate =50/100 = 0.5 mole

Molarity = mole per litre of volume

Molarity = 0.5 /0.25 = 2mole/litre

Explanation:

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lisabon 2012 [21]3 years ago

6 0

Answer:

$mass \: of \: solute = 50 g \\ volume \: of \: the \: solution = 250ml \\ molar \: mass \: of \: solute \: = 100 \frac{g}{mol} \\ molarity = \frac{mole}{volume} \\ = \frac{ \frac{50}{100} }{250 \times {10}^{ - 3} } \\ = \frac{.5 \times {10}^{3} }{250} \\ = \frac{500}{250} \\ = 2mol \\ thank \: you$

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3 years ago

The pH of a solution is measured eight times by one operator using the same instrument. She obtains the following data: 7.15, 7.

sergiy2304 [10]

Answer:

7.186

Explanation:

The mean is the average of some given data from a sample point.

To calculate the mean, we use the formula below:

Mean = ∑fx/∑f

Where f = frequency

x = sample data

From the given pH of the solutions, we can form a table:

x f fx

7.15 1 7.15

7.16 1 7.16

7.18 1 7.18

7.19 1 7.19

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7.21 1 7.21

Now ∑fx = 7.15 +7.16 +7.18 + 7.19 + 7.20 + 7.21 = 57.49

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The mean = $\frac{57.49}{8}$ = 7.18625 = 7.186

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3 years ago

How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg

Afina-wow [57]

Answer : The mass of $PbSO_4$ needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of $PbCrO_4$ .

$\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole$

Now we have to calculate the moles of $PbSO_4$ .

The balanced chemical reaction will be,

$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$

So, 0.005 mole of $PbCrO_4$ produced from 0.005 mole of $PbSO_4$

Now we have to calculate the mass of $PbSO_4$

$\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4$

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Therefore, the mass of $PbSO_4$ needed are, 1.515 grams.

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3 years ago

A- is a weak base. which equilibrium corresponds to the equilibrium constant ka for ha?

vekshin1

Answer:

$K_a=\frac{[H^+][A^-]}{[HA]}$

Explanation:

ka is defined as the dissociation constant of an acid. It is defined as the ratio of concentration of products to the concentration of reactants.

For the dissociation of weak acid, the chemical equation follows:

$HA\rightleftharpoons H^++A^-$

The equilibrium constant is defined by the equilibrium concentration of products over reactants:

$K_a=\frac{[H^+][A^-]}{[HA]}$

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kkurt [141]

Answer:

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3 years ago

What is the molarity of 50gram of calcium carbonate is dissolved in 250ML of water​

What is the molarity of 50gram of calcium carbonate is dissolved in 250ML of water