Is H2O polar or non polar?

Chemistry

2 answers:

otez555 [7]2 years ago

8 0

Answer:

Explanation:

H2O is a polar molecule

Pie2 years ago

4 0

Answer:

polar covalent molecule

Explanation:

the unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule means that water has two pole a positive and a negative.

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Consider 0.01 m aqueous solutions of each of the following. a) NaI; b) CaCl2; c) K3PO4; and d) C6H12O6 (glucose) Arrange the sol

stealth61 [152]

Answer:

The solutions are ordered by this way (from lowest to highest freezing point): K₃PO₄ < CaCl₂ < NaI < glucose

Option d, b, a and c

Explanation:

Colligative property: Freezing point depression

The formula is: ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

We need to determine the i, which is the numbers of ions dissolved. It is also called the Van't Hoff factor.

Option d, which is glucose is non electrolyte so the i = 1

a. NaI → Na⁺ + I⁻ i =2

b. CaCl₂ → Ca²⁺ + 2Cl⁻ i =3

c. K₃PO₄ → 3K⁺ + PO₄⁻³ i=4

Potassium phosphate will have the lowest freezing point, then we have the calcium chloride, the sodium iodide and at the end, glucose.

7 0

3 years ago

A substance with a high [H ] would likely have which additional characteristics? a high [OHĂ˘â‚¬"" ] and a high pOH a low [OHĂ˘â

viktelen [127]

The negative log function that determines the acidity or alkalinity by hydronium ion concentration is called pH.

The substance having high $\rm [H]$ will have:

Option B. A low $\rm [OH ^{-}]$ and a high $\rm pOH$

This characteristic can be explained as:

The concentrations of $\rm [H^{+}]$ and $\rm [OH ^{-}]$ are inversely dependent on each other so when the concentration of raises then the concentration of $\rm [OH ^{-}]$ drops and vice versa.

The pH of a solution or substance is calculated with the help of:

$\rm pH = \rm - log \rm [H^{+}]$

From the formula, it can be deduced that when the concentration of $\rm [H^{+}]$ is high then the pH has a low value and it means that the solution is acidic.