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3 years ago

At what Celsius temperature does 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa?

Chemistry

1 answer:

shepuryov [24]3 years ago

8 0

382.85 Celsius is the temperature does 0.750 moles of an ideal gas occupy a volume of 35.9 L at 114 kPa.

Explanation:

Given data:

number of moles of the gas = 0.75 moles

volume of the gas = 35.9 liters

pressure of the gas = 114 KPa or 1.125 atm

R = 0.0821 latm/moleK

temperature of the gas T = ?

The equation used to calculate temperature from above data is ideal gas law equation.

the equation is :

PV = nRT

T = $\frac{PV}{nR}$

Putting the values in the above rewritten equation:

T = $\frac{1.125 X 35.9}{0.75 X 0.0821}$

T = 655.9 K

To convert kelvin into celsius, formula used is

K = 273.15+ C

putting the values in the equation

C = 656 - 273.15

= 382.85 Celsius

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Ethylene produced by fermentation has a specific gravity of 0.787 at 25 degree Celsius. What is the volume of 125g of ethanol at

WITCHER [35]

Answer: The volume of given amount of ethanol at this temperature is 159.44 mL

Explanation:

Specific gravity is given by the formula:

$\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}$

We are given:

Density of water = 0.997 g/mL

Specific gravity of ethanol = 0.787

Putting values in above equation, we get:

$0.787=\frac{\text{Density of a substance}}{0.997g/mL}\\\\\text{Density of a substance}=(0.787\times 0.997g/mL)=0.784g/mL$

Density is defined as the ratio of mass and volume of a substance.

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$ ......(1)

Given values:

Mass of ethanol = 125 g

Density of ethanol = 0.784 g/mL

Putting values in equation 1, we get:

$\text{Volume of ethanol}=\frac{125g}{0.784g/mL}=159.44mL$

Hence, the volume of given amount of ethanol at this temperature is 159.44 mL

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3 years ago

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igomit [66]

Answer:

Explanation:

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3 years ago

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3 years ago

For the reaction NH3 + NO → N2 + H2O, identify the reactants, products, and their coefficients once the equation is balanced. (3

nirvana33 [79]

Answer:

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Explanation:

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Lapatulllka [165]

Answer:

See explanation

Explanation:

We must first write the equation of the reaction as follows;

C3H8 + 5O2 ----> 3CO2 + 4H2O

Now;

We obtain the number of moles of C3H8 = 132.33g/44g/mol = 3 moles

So;

1 mole of C3H8 yields 3 moles of CO2

3 moles of C3H8 yields 3 × 3/1 = 9 moles of CO2

We obtain the number of moles of oxygen = 384.00 g/32 g/mol = 12 moles

So;

5 moles of oxygen yields 3 moles of CO2

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We can now decide on the limiting reactant to be C3H8

Therefore;

Mass of CO2 produced = 9 moles of CO2 × 44 g/mol = 396 g of CO2

Again;

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Hence;

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b) Actual yield = 269.34 g

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Therefore;

% yield = actual yield/theoretical yield × 100/1

Substituting values

% yield = 269.34 g /396 g × 100

% yield = 68%

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3 years ago