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3 years ago

At what Celsius temperature does 0.750 mol of an ideal gas occupy a volume of 35.9 L at 114 kPa?

Chemistry

1 answer:

shepuryov [24]3 years ago

8 0

382.85 Celsius is the temperature does 0.750 moles of an ideal gas occupy a volume of 35.9 L at 114 kPa.

Explanation:

Given data:

number of moles of the gas = 0.75 moles

volume of the gas = 35.9 liters

pressure of the gas = 114 KPa or 1.125 atm

R = 0.0821 latm/moleK

temperature of the gas T = ?

The equation used to calculate temperature from above data is ideal gas law equation.

the equation is :

PV = nRT

T = $\frac{PV}{nR}$

Putting the values in the above rewritten equation:

T = $\frac{1.125 X 35.9}{0.75 X 0.0821}$

T = 655.9 K

To convert kelvin into celsius, formula used is

K = 273.15+ C

putting the values in the equation

C = 656 - 273.15

= 382.85 Celsius

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What is the mole fraction of NaOH in an aqueous solution that

astraxan [27]

Answer:

The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

Explanation:

We are given that

Aqueous solution that contains 22.9% NaOH by mass means

22.9 g NaOH in 100 g solution.

Mass of NaOH(WB)=22.9 g

Mass of water =100-22.9=77.1

Na=23

O=16

H=1.01

Molar mass of NaOH(MB)=23+16+1.01=40.01

Number of moles = $\frac{Given\;mass}{Molar\;mass}$

Using the formula

Number of moles of NaOH $(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}$

$n_B=0.572moles$

Molar mass of water=16+2(1.01)=18.02g

Number of moles of water $(n_A)=\frac{77.1}{18.02}$

$n_A=4.279 moles$

Now, mole fraction of NaOH

= $\frac{n_B}{n_B+n_A}$

$=\frac{4.279}{0.572+4.279}$

=0.882

Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

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3 years ago

Which of the following choices results in a decrease in the overall density of a product? Question 5 options: Increase the volum

Elza [17]

Answer:

When the volume of product increases.

When the weight of the product decreases.

Option (a) and (d) are correct.

Explanation:

The overall density of the product can be decreased:

a. Increase the volume of the product (and keep the material same)

d. Decrease the weight of the product ( and keep the same material ).

Density is calculated as the ratio of mass to the volume.

Density is inversely related to volume and directly related to mass.

So, when the mass of the product is increased then the density will increase keeping the material same. Density will also increase when the volume of the product decreased.

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4 years ago

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Su şeker karışımını ayırma yöntemi nedir arkadaşlar

Alinara [238K]

<span>Suda karıştırıldıysa, kaynatma ile hacmi azaltmayı deneyebilirsiniz, ancak bir veya daha fazla çözüm bulunmaması durumunda çok uzun sürecektir. Çözeltiye fazla aseton ilavesi, filtrelenebilen tuzu çöktürmelidir. Asetondan buharlaşma şeker üretecektir.</span>

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4 years ago

You need to determine the specific gravity of a sample. After putting the sample on a lab scale, you know it has a mass of 85 gr

BlackZzzverrR [31]

Answer:

Specific gravity of the sample = 8.947

Explanation:

Specific gravity of a substance is defined as the density of that substance divided by the density of water.

Density of water = 1000g/l

Density of substance = mass/volume

= 85/9.5 x 10^-3

= 8947.37 g/l

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3 years ago

Chlorine pentafluoride gas is collected at -17.0 °C in an evacuated flask with measured volume of 35.0 L. When all the gas has b

Svet_ta [14]

Answer:

1. The mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of Chlorine pentafluoride, ClF5, is 0.3mole

Explanation:

1. To solve the mass of Chlorine pentafluoride, ClF5, first, let us calculate the molar mass of ClF5. This is illustrated below:

Molar Mass of ClF5 = 35.5 + (5 x 19) = 35.5 + 95 = 130.5g/mol

From the ideal gas equation:

PV = nRT (1)

Recall:

Number of mole(n) = mass (m) /Molar Mass(M)

n = m/M

Now substituting the value of n in equation 1, we have:

PV = nRT

PV = mRT/M

Now we can obtain the mass of Chlorine pentafluoride ClF5 as follow:

Data obtained from the question include:

T (temperature) = -17.0 °C = - 17 + 273 = 256K

V (volume) = 35L

P (pressure) = 0.180 atm

R (gas constant) = 0.082atm.L/Kmol

m (mass of Chlorine pentafluoride) =?

M (molar mass of Chlorine pentafluoride) = 130.5g/mol

PV = mRT/M

0.180 x 35 = m x 0.082 x 256/ 130.5

Cross multiply to express in linear form as shown below:

m x 0.082 x 256 = 0.180x35x130.5

Divide both side by 0.082 x 256

m = (0.180x35x130.5) /(0.082x256)

m = 39.16g

Therefore, the mass of Chlorine pentafluoride, ClF5, is 39.16g

2. The number of mole of ClF5 can be obtained as follow:

Mass of ClF5 = 39.16g

Molar Mass of ClF5 = 130.5g/mol

Mole of ClF5 =?

Number of mole = Mass /Molar Mass

Mole of ClF5 = 39.16/130.5g

Mole of ClF5 = 0.3mole

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4 years ago

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