The magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.
To find the answer, we have to know more about the force experienced between two charges.
<h3>How to find the
force experienced between two charges?</h3>
- We have to find the force experienced between two charges,
where, k=8.99*10^9.
- Thus, by substitution, the force will be,
Thus, we can conclude that, the magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.
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Answer:
-6.8 m/s²
Explanation:
Given:
v₀ = 30.5 m/s
v = 0 m/s
t = 4.5 s
Find: a
a = (v − v₀) / t
a = (0 m/s − 30.5 m/s) / 4.5 s
a = -6.8 m/s²
The displacement ........................
Answer:
The time it takes the ball to fall 3.8 meters to friend below is approximately 0.88 seconds
Explanation:
The height from which the student tosses the ball to a friend, h = 3.8 meters above the friend
The direction in which the student tosses the ball = The horizontal direction
Given that the ball is tossed in the horizontal direction, and not the vertical direction, the initial vertical component of the velocity of the ball = 0
The equation of the vertical motion of the ball can therefore, be represented by the free fall equation as follows;
h = 1/2 × g × t²
Where;
g = The acceleration due gravity of the ball = 9.81 m/s²
t = The time of motion to cover height, h
Then height is already given as h = 3.8 m
Substituting gives;
3.8 = 1/2 × 9.81 × t²
t² = 3.8/(1/2 × 9.81) ≈ 0.775 s²
∴ t = √0.775 ≈ 0.88 seconds
The time it takes the ball to fall 3.8 meters to friend below is t ≈ 0.88 seconds.
Answer:
the pressure due to the water on the diver is 200,000 pascal
pressure = height × density × acceleration due to gravity
p = 20×1000×10
p=200,000 pascal
