Answer:
The angle of projection is 12.26⁰.
Explanation:
Given;
initial position of the dart, h₀ = 1.50 m
height above the ground reached by the dart, h₁ = 1.73 m
maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m
velocity of the dart, u = 10 m/s
The maximum height reached by the projectile is calculated as;

where;
θ is angle of projection
g is acceleration due to gravity = 9.8 m/s²

Therefore, the angle of projection is 12.26⁰.
Answer:
E = 5291.00 N/C
Explanation:
Expression for capacitance is

where
A is area of square plate
D = DISTANCE BETWEEN THE PLATE




We know that capacitrnce and charge is related as


v = 9.523 V
Electric field is given as

= 
E = 5291.00 V/m
E = 5291.00 N/C
Answer:

Explanation:
As we know that the charge per unit length of the long cylinder is given as

here we know that the electric field between two cylinders is given by

now we know that electric potential and electric field is related to each other as





Answer:
18.4 m
Explanation:
(a)
The known variables in this problem are:
u = 1.40 m/s is the initial vertical velocity (we take downward direction as positive direction)
t = 1.8 s is the duration of the fall
a = g = 9.8 m/s^2 is the acceleration due to gravity
(b)
The vertical distance covered by the life preserver is given by

If we substitute all the values listed in part (a), we find

Answer:
here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa
Explanation:
As wee know that the amplitude of the wave will decide the energy of the wave
Here we know that energy density of electromagnetic wave is given as

now we have

so here we can say that intensity of the wave at the given distance from the source is given by formula

so here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa.