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Angelina_Jolie [31]

3 years ago

9

A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation

?

1 answer:

qaws [65]3 years ago

8 0

Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its <em>wavelength</em> and <em>temperature</em> is given by Wien's displacement law.

$\lambda_{max}=\frac{b}{T}$

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

$T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K }{0.21m} =0.014K$

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b)

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$T_2 = 386 \ K \\ \\T_1 = (89.8 + 273)K = 362.8 \ K$

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$In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})$

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