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pantera1 [17]
2 years ago
8

-5(c-4)= a*-20-5c b*20-5c c*20+5c ???????

Mathematics
2 answers:
Masteriza [31]2 years ago
7 0

Answer:

b

Step-by-step explanation:

distributive property-

-5c-(-20) which is -5c+20 which can also be 20-5c

Natalija [7]2 years ago
6 0
1
Distribute
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Solution
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Answer:

a) z=\frac{0.684 -0.58}{\sqrt{\frac{0.58(1-0.58)}{114}}}=2.250  

b) p_v =2*P(z>2.250)=0.0244  

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Step-by-step explanation:

Data given and notation

n=114 represent the random sample taken

\hat p=0.684 estimated proportion of people that their approval rating might have changed

p_o=0.58 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Hypothesis

We need to conduct a hypothesis in order to test the claim that true proportion of people that their approval rating might have changed is 0.58 or no.:  

Null hypothesis:p=0.58  

Alternative hypothesis:p \neq 0.58  

Part a

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.684 -0.58}{\sqrt{\frac{0.58(1-0.58)}{114}}}=2.250  

Part b: Statistical decision  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>2.250)=0.0244  

If we compare the p value and the significance level given we see that p_v we have enough evidence to reject the null hypothesis at 5% of significance.

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