Answer:
speed = 1.24 × 10⁸m/s
frequency = 4.74 × 10¹⁴Hz
wavelength = 262nm
Explanation:
the speed of the helium-neon light in zircon is given by,
v = c / n
c = 3 × 10⁸m/s is the speed of light in vacuum (and in air)
n = 2.419 is the refractive index of diamond
v = 3 × 10⁸ / 2.419
= 1.24 × 10⁸m/s
(b) Frequency
The wavelength of the light in air is:
λ₀ = 632.8 × 10⁻⁹
The frequency of the light does not depend on the medium, so it is equal in air and in diamond. Therefore, we can calculate the frequency by using the speed of light in air and the wavelength in air:
f₀ = c / λ₀
= 3 × 10⁸ / 632.8 × 10⁻⁹
= 4.74 × 10¹⁴Hz
and the frequency of the light indiamond is the same:
f¹ = f₀ = 4.74 × 10¹⁴Hz
(c) Wavelength
To calculate the wavelength of the light in daimond, we can use the relationship between speed of light in diamond and frequency:
λ¹ = v / f¹
= 1.24 × 10⁸ / 4.74 × 10¹⁴
= 2.62 × 10⁻⁷m
= 262nm
1. Velocity and 2. Acceleration
Answer:
R = 1,746 Ω
Explanation:
The power dissipated in the circuit is
P = V I = V² / R
Let's find the current
R = V² / P
Let's calculate
R = 13²/81
R = 2,096 Ω
This is total resistance
R_total = R + r
R = R_total - r
R = 2,096 -0,350
R = 1,746 Ω
Answer:
727.67 km
Explanation:
Sine they have Same distance D
distance = speed * time
D = 5.08t
D = 8.3312(t+55.9)
so
5.08t = 8.3312(t+55.9) t in
3.2512t = 465.71
t = 143.2s
Subtitute t
D=5.08 t
= 5.08 × 143.2
= 727.67km
Explanation:
It is given that,
Mass of the object, m = 0.8 g = 0.0008 kg
Electric field, E = 534 N/C
Distance, s = 12 m
Time, t = 1.2 s
We need to find the acceleration of the object. It can be solved as :
m a = q E.......(1)
m = mass of electron
a = acceleration
q = charge on electron
"a" can be calculated using second equation of motion as :
a = 16.67 m/s²
Now put the value of a in equation (1) as :
q = 0.0000249 C
or
Hence, this is the required solution.
