All categories

2 years ago

1.Which car has zero acceleration?2. which car is decelerating?

Physics

1 answer:

Ivanshal [37]2 years ago

5 0

Answer:

1. B has no acceleration because the straight line shows that it's a constant speed not speeding up or down.

2. A because you can see the decline in speed as time goes on

You might be interested in

I NEED HELP ASAP WILL MARK BRAINLIEST:

Evgen [1.6K]

Answer:

It is b for sure.

Explanation:

because they are examining urine now that's pure science.

7 0

3 years ago

Insulators are materials that reduce heat flow. Nature uses many types of insulation to protect animals from losing too much hea

katrin2010 [14]

Answer:

This has all the answer (Data sheet, graph, answers to the questions, and the summary) :)

6 0

2 years ago

4- Protein foods?? pls answer these i really need these

vampirchik [111]

The #1 answer would be meats and eggs. But, as a veggan, I present you with meatless protien-rich food!

1 - Pea protein (used in Beyond Meat, which tastes just like meat btw!)

2 - Soy protein such as tofu

3 - Nuts

4 - Beans! oml so many beans have MORE protien than meat!! ikr!?!?

may I have Brainliest pls =)

8 0

2 years ago

A playground merry-go-round has a mass of 115 kg and a radius of 2.50 m and it is rotating with an angular velocity of 0.520 rev

tatuchka [14]

Answer:

$W_f = 2.319 rad/s$

Explanation:

For answer this we will use the law of the conservation of the angular momentum.

$L_i = L_f$

so:

$I_mW_m = I_sW_f$

where $I_m$ is the moment of inertia of the merry-go-round, $W_m$ is the initial angular velocity of the merry-go-round, $I_s$ is the moment of inertia of the merry-go-round and the child together and $W_f$ is the final angular velocity.

First, we will find the moment of inertia of the merry-go-round using:

I = $\frac{1}{2}M_mR^2$

I = $\frac{1}{2}(115 kg)(2.5m)^2$

I = 359.375 kg*m^2

Where $M_m$ is the mass and R is the radio of the merry-go-round

Second, we will change the initial angular velocity to rad/s as:

W = 0.520*2 $\pi$ rad/s

W = 3.2672 rad/s

Third, we will find the moment of inertia of both after the collision:

$I_s = \frac{1}{2}M_mR^2+mR^2$

$I_s = \frac{1}{2}(115kg)(2.5m)^2+(23.5kg)(2.5m)^2$

$I_s = 506.25kg*m^2$

Finally we replace all the data:

$(359.375)(3.2672) = (506.25)W_f$

Solving for $W_f$ :

$W_f = 2.319 rad/s$

7 0

2 years ago

The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth

ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

$\frac{P_{1} }{\\P_2}$ = $\frac{density * g * h_1}{density * g * h_2}$

So $\frac{39}{P_2}$ = $\frac{3}{9}$

Or P₂= 39 * 3 = 117 kPa

5 0

3 years ago

1.Which car has zero acceleration?2. which car is decelerating? ​

1.Which car has zero acceleration?2. which car is decelerating?