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Mashutka [201]
3 years ago
7

A pair of students determining the molarity of their unknown HCl solution calculates the concentration to be 0.0961 M on their f

irst trial and 0.104 M on their second trial. Do they need to run a third trial
Chemistry
2 answers:
Varvara68 [4.7K]3 years ago
7 0

Answer:

Yes.

Explanation:

It should be noted that the meaning of molarity is the ratio of moles of solute per liter of solution.

It should be understood that when determining or finding the molarity of an unknown compound ,the process should be performed or carried out at least 3 times. This is done to remove any form of doubt.

The first calculated value for the concentration of the compound will be regarded as rough value, while the second and the third will be regarded as the first and second values respectively.

In this case, the third value for the concentration of HCl will be calculated to for confirmation of other value, that is to be finally sure of its concentration.  

Katyanochek1 [597]3 years ago
5 0

Answer:

Yes.

Explanation:

For a typical experiment, you should plan to repeat it at least three times (more is better).

The value gotten in the first trial is not close to the value gotten from the second trial.

The solution to these problems is to do repeated trials. Repeated trials are when you do a measurement multiple times - at least three, commonly five, but the more the better. When you measure something once, the chance that the number you get is accurate is much lower. But if you measure it several times, you can take an average of those numbers and get a result that is much closer to the truth.

Repeating a trial gives a RELIABLE result.

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At a certain temperature, 0.900 mol of SO3 is placed in a 2.00-L container.
Goryan [66]

Answer:

Kc = 2.34 mol*L

Explanation:

The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.

A + B ⇄ C + D

Kc = [C] * [D] / [A] * [B]

According to the reaction

Kc = [SO2]^2 * [O2]^2 / [SO3]^2

Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3

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Kc = [0.260]^2 + [0.130]^2 / [0.190]^2

Kc = 2.34 mol*L

3 0
3 years ago
Draw the aromatic compound toluene (methylbenzene). show all hydrogen atoms, including those on the ring.
Otrada [13]

Aromatic compound has continuous cyclic structure with( 4n+2)π electrons (Huckels rule), where n = 0,1,2…

Here number of pi electron are 6, where 4 from two double bond and 2 from nitrogen non-bonding electrons, hence it has total 6 pi electrons, therefore

6= ( 4n+2)π

4 = 4n  

n =1

 

Hence it is an aromatic compound  

 


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What happens to a gas that is enclosed in a rigid container when the temperature of the gas is increased?
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