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denis-greek [22]
2 years ago
15

A person weighing 600 Newtons gets on an elevator. The elevator lifts the person 6 meters in 10 seconds. How much power was used

?
Physics
1 answer:
Svetlanka [38]2 years ago
4 0

Answer:

The power used is 360 Watts.

Explanation:

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A boy is pulling a 150 kg crate with a force of 1150 N. If the crate experiences a frictional force of 490 N, find:
valentina_108 [34]
<h3><u>For the aceleration:</u></h3>

First, let's find the resultant, and <u>applicate 2nd law of Newton</u> using the resultant, so:

R = ma

F - Ff = ma

Data:

F = Force = 1150 N

Ff = Friction force = 490 N

m = Mass = 150 kg

a = Aceleraction = ?

Replacing according our data:

1150 N - 490 N = 150 kg * a

660 N = 150 kg * a

660 N / 150 kg = a

a = 4,4 m/s²   ← Aceleration of the object

<h3><u>For the normal force:</u></h3>

The normal force IS NOT the resultant force, the normal force's the force between the ground and the object, in another words, is the weight of the object, and for the weight:

w = mg

w = 150 kg * 10 m/s²

w = 1500 N   ← Normal force between object and ground.

7 0
3 years ago
Two wires are stretched between two fixed supports and have the same length. One wire A there is a second-harmonic standing wave
lina2011 [118]

(a) Greater

The frequency of the nth-harmonic on a string is an integer multiple of the fundamental frequency, f_1:

f_n = n f_1

So we have:

- On wire A, the second-harmonic has frequency of f_2 = 660 Hz, so the fundamental frequency is:

f_1 = \frac{f_2}{2}=\frac{660 Hz}{2}=330 Hz

- On wire B, the third-harmonic has frequency of f_3 = 660 Hz, so the fundamental frequency is

f_1 = \frac{f_3}{3}=\frac{660 Hz}{3}=220 Hz

So, the fundamental frequency of wire A is greater than the fundamental frequency of wire B.

(b) f_1 = \frac{v}{2L}

For standing waves on a string, the fundamental frequency is given by the formula:

f_1 = \frac{v}{2L}

where

v is the speed at which the waves travel back and forth on the wire

L is the length of the string

(c) Greater speed on wire A

We can solve the formula of the fundamental frequency for v, the speed of the wave:

v=2Lf_1

We know that the two wires have same length L. For wire A, f_1 = 330 Hz, while for wave B, f_B = 220 Hz, so we can write the ratio between the speeds of the waves in the two wires:

\frac{v_A}{v_B}=\frac{2L(330 Hz)}{2L(220 Hz)}=\frac{3}{2}

So, the waves travel faster on wire A.

7 0
3 years ago
Why is copper a good conductor?
IgorLugansk [536]
Copper conducts electricity
4 0
3 years ago
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Which of the following is true about this lever?
zysi [14]

As we can see here the lever has two forces at two ends

1. 300 N

2. 200 N

now we need to find the Torque on the lever about the fulcrum

so we will have

1. clockwise torque due to force at right end is

\tau_1 = d_1F_1

\tau_1 = 6(200) = 1200 Nm

2. counterclockwise torque due to force at left end

\tau_2 = d_2F_2

\tau_2 = 1(300) = 300 Nm

so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction

so <u>it will rotate clockwise</u>

6 0
3 years ago
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an ice sheet 5m thick covers a lake that is 20m deep. at what is the temperature of the water at the bottom of the lake?
muminat

Answer:

4°C

Explanation:

Water is densest at 4°C.  Since dense water sinks, the bottom of the lake will be 4°C.

6 0
4 years ago
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