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denis-greek [22]
2 years ago
15

A person weighing 600 Newtons gets on an elevator. The elevator lifts the person 6 meters in 10 seconds. How much power was used

?
Physics
1 answer:
Svetlanka [38]2 years ago
4 0

Answer:

The power used is 360 Watts.

Explanation:

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_________ are exchanged or shared during the formation of a chemical bond. A) Orbitals B) Sublevels C) Valence electrons D) Suba
d1i1m1o1n [39]

Answer:

C) Valence electrons.

Explanation:

When a chemical bond is formed it is the electrons that are shared and it is they that hold the two atoms together due to the coulomb forces between the positive nuclei and the valence electrons. To put in in another way, both nuclei of the bond want the electrons, but neither can get them, regardless, they hold on to them, and this is what makes a chemical bond.

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3 years ago
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Inductive charging is used to wirelessly charge electronic devices ranging from toothbrushes to cell phones. Suppose the base un
statuscvo [17]

The time required (in s) for the magnetic field to decrease to zero from its maximum value is 1.2 x 10⁻⁶ s.

<h3>Faraday's law of electromagnetic induction</h3>

Faraday's first law of electromagnetic induction states, “Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced.

emf = NdФ/dt

emf = NBA/t

where;

  • N is number of turns of the coil
  • A is area of the coil
  • B is magnetic field
  • t is time

The time required (in s) for the magnetic field to decrease to zero from its maximum value is calculated as follows;

t = NBA/emf

t = (16 x 1.1 x 10⁻³ x 3.75 x 10⁻⁴) / (5.5)

t = 1.2 x 10⁻⁶ s

Thus, the time required (in s) for the magnetic field to decrease to zero from its maximum value is 1.2 x 10⁻⁶ s.

Learn more about magnetic field here: brainly.com/question/7802337

#SPJ1

7 0
2 years ago
How far should flammable material be kept from electrical panels?
MakcuM [25]
Not close because it’ll blow up if too close.
4 0
2 years ago
A 4.9-MeV (kinetic energy) proton enters a 0.28-T field, in a plane perpendicular to the field. Part APart complete What is the
BartSMP [9]

Answer:

r=1.14m

Explanation:

\theta is the angle between the velocity and the magnetic field. So, the magnetic force on the proton is:

F_m=qvBsen\theta\\F_m=qvBsen(90^\circ)\\F_m=qvB

A charged particle describes a semicircle in a uniform magnetic field. Therefore, applying Newton's second law to uniform circular motion:

F_m=F_c\\qvB=F_c(1)

F_c is the centripetal force and is defined as:

F_c=m\frac{v^2}{r}

Here v is the proton's speed and r is the radius of the circular motion. Replacing this in (1) and solving for r:

qvB=\frac{mv^2}{r}\\r=\frac{mv^2}{qvB}\\r=\frac{mv}{qB}

Recall that 1 J is equal to 6.242*10^{12}MeV, so:

4.9MeV*\frac{1J}{6.242*10^{12}MeV}=7.85*10^{-13}J

We can calculate v from the kinetic energy of the proton:

K=\frac{mv^2}{2}\\\\v=\sqrt{\frac{2K}{m}}\\v=\sqrt{\frac{2(7.85*10^{-13}J)}{1.67*10^{-27}kg}}\\v=3.06*10^{7}\frac{m}{s}

Finally, we calculate the radius of the proton path:

r=\frac{mv}{qB}\\r=\frac{1.67*10^{-27}kg(3.06*10^{7}\frac{m}{s})}{1.6*10^{-19}C(0.28T)}\\r=1.14m

8 0
4 years ago
Can you answer my question please go to my profile ​
ad-work [718]

Answer:

what do u need help on

I went to ur profile and I don't know what I'm looking for

8 0
3 years ago
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