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kondor19780726 [428]
2 years ago
5

What is the Common denominator?

Mathematics
1 answer:
melomori [17]2 years ago
7 0

[] The fractions are

        \frac{12}{21}\\\\\frac{4}{7}

[] I see that 21 is a multiple of 7, so this one will be simple to solve.

-> 21 / 7 = 3, so we can do the following:

             \frac{4*3}{7*3}=\frac{12}{21}

[] Now they have a common denominator of <u>21</u>

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

We need to find the elements of matrix B.

Let B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}

Substitute the value of matrix.

\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

After addition of two matrix we get

\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

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b_{11}+15=1\Rightarrow b_{11}=-14

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b_{21}+0=4\Rightarrow b_{21}=4

b_{22}+1=0\Rightarrow b_{22}=-1

b_{23}+2=2\Rightarrow b_{23}=0

Therefore, the elements of matrix B are b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0.

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