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Dovator [93]
3 years ago
12

What is a rock cycle?

Physics
1 answer:
DochEvi [55]3 years ago
7 0

Answer:

an idealized cycle of processes undergone by rocks in the earth's crust

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A 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. The
qaws [65]

let the length of the beam be "L"

from the diagram

AD = length of beam = L

AC = CD = AD/2 = L/2

BC = AC - AB = (L/2) - 1.10

BD = AD - AB = L - 1.10

m = mass of beam = 20 kg

m₁ = mass of child on left end = 30 kg

m₂ = mass of child on right end = 40 kg

using equilibrium of torque about B

(m₁ g) (AB) = (mg) (BC) + (m₂ g) (BD)

30 (1.10) = (20) ((L/2) - 1.10) + (40) (L - 1.10)

L = 1.98 m

4 0
2 years ago
A radio has a 1.3 A current. If it has a resistance of 35 Ω, what is the potential difference?
DedPeter [7]

Answer:

22

Explanation:

7 0
3 years ago
Read 2 more answers
Can the tangent line to a velocity vs. time graph ever be vertical? Explain.
34kurt

Answer:

No. Because it would correspond to zero Instantaneous acceleration.

Explanation:

hope this helps

7 0
3 years ago
A bicycle rider has a speed of 19.0 m/s at a height of 55.0 m above sea level when he begins coasting down hill. The mass of the
lukranit [14]

Answer:

The mechanical energy of the rider at any height will be 6.34 × 10⁴ J.

Explanation:

Hi there!

The mechanical energy of the rider is calculated as the sum of the gravitational potential energy plus the kinetic energy. Since there are no dissipative forces (like friction), the mechanical energy of the rider at a height of 55.0 m above the sea level will be the same at a height of 25.0 m (or at any height), because the loss in potential energy will be compensated by a gain in kinetic energy, according to the law of conservation of energy.

Then, calculating the potential and kinetic energy at 55.0 m and 19 m/s, we can obtain the mechanical energy that will be constant:

Mechanical energy = PE + KE

Where:

PE = potential energy.

KE = kinetic energy.

The potential energy is calculated as follows:

PE = m · g · h

Where:

m = mass of the object.

g = acceleration due to gravity.

h = height.

Then, the potential energy of the rider will be:

PE = 88.0 kg · 9.81 m/s² · 55.0 m = 4.75 × 10⁴ J

The kinetic energy is calculated as follows:

KE = 1/2 · m · v²

Where "m" is the mass of the object and "v" its velocity. Then:

KE = 1/2 · 88.0 kg · (19.0 m/s)²

KE = 1.59 × 10⁴ J

The mechanical energy of the rider will be:

Mechanical energy = PE + KE = 4.75 × 10⁴ J + 1.59 × 10⁴ J = 6.34 × 10⁴ J

This mechanical energy is constant because when the rider coast down the hill, its potential energy is being converted into kinetic energy, so that the sum of potential energy plus kinetic energy remains constant.

5 0
3 years ago
al aplicar una fuerza de 2 N sobre un muelle este se alarga 4cm.¿cuanto se alargara si la fuerza es el triple?¿que fuerza tendri
3241004551 [841]

1) 12 cm

2) 3 N

Explanation:

1)

The relationship between force and elongation in a spring is given by Hooke's law:

F=kx

where

F is the force applied

k is the spring constant

x is the elongation

For the spring in this problem, at the beginning we have:

F=2 N

x=4 cm

So the spring constant is

k=\frac{F}{x}=\frac{2N}{4 cm}=0.5 N/cm

Later, the force is tripled, so the new force is

F'=3F=3(2)=6 N

Therefore, the new elongation is

x'=\frac{F'}{k}=\frac{6}{0.5}=12 cm

2)

In this second problem, we know that the elongation of the spring now is

x=6 cm

From part a), we know that the spring constant is

k=0.5 N/cm

Therefore, we can use the following equation to find the force:

F=kx

And substituting k and x, we find:

F=(0.5)(6)=3 N

So, the force to produce an elongation of 6 cm must be 3 N.

6 0
3 years ago
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