Δλ = 3.103 m.
To solve this problem we have to know the speed of sound in both elements water and ice.
Element Speed of sound
Water (25°C) 1493 m/s
Ice 3200 m/s
The velocity of a wave is given by the equation v = λf, where λ is the wavelength, and f is the frecuency of the wave.
In order to calculate the wavelength we have to clear λ in the equation v = λf, resulting:
λ = v/f
Calculating the wavelength in both elements:
λ(water) = 1493 m/s / 550 Hz = 2.715 m
λ(ice) = 3200 m/s / 550 Hz = 5.818 m
So, the difference in wavelength between the wave produced in ice and the wave produced in water is:
Δλ = λ(water) - λ(ice) = 5.818 m - 2.715 m
Δλ = 3.103 m
Answer:
The first one is graph and the second one is electronic balance, third computer then data table and the last is graduated cylinder.
Explanation:
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Answer:
Explanation:
Given:
- original frequency of sound wave,
- speed of the sound source,
- original speed of sound wave from the source,
<u>According to the Doppler's effect:</u>
The sound is reflected from the wall and the source is moving towards the wall and observer is also riding the same source.
The velocity of the observer, 
Answer:
θ = 30⁰
Explanation:
We have been given two wave displacement equations,
........(1)
........(2)
The waves will have same displacements when 
(say)
Therefore, operating (2) - (1), we get,
or, 
(since, sin 30⁰ = 0.5)
We can check the answer by putting 
in equations (1) and (2),
Answer:
An aircraft, flying in the vicinity of 18,000 ft altitude from west to east over the US at 12 Z today, will __LOSE___ altitude if the altimeter is not corrected
