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Solnce55 [7]
3 years ago
9

Describe four characteristics of S-block elements​

Chemistry
1 answer:
diamong [38]3 years ago
7 0

1. s block elements have spherical s orbital as

their outermost orbital.

2. Since s orbital can accommodate a maximum of 2 electrons, each one of these elements have 1 or two electrons.

3. These s electrons are lost very easily to form

monopositive ions by Isoing one electron in the

outermost orbital or dipositive ions by losing 2

electrons.

4. They have low ionisation potentials and low electronegativities.

5. They are good conductors of heat and electricity, excepting H2 and He.

6. They are silvery, shiny metallic substances, (with the exception of hydrogen and helium which gaseous nonmetals).

7. They are malleable and ductile, i.e., we can

make sheets and wires from them, (exception:

H2, He)

8. They readily form ionic salts with most nonmetals.

hope it helps plzzz mark as brainliest

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Pls help fast!! Test due soon!!!
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its compound option c compound comprises of two or more atoms

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Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a
I am Lyosha [343]
First off, the chemical equation needs to be balanced. Since there are 2 oxygen atoms in the reactants, we must produce 2 moles of MgO, which means we need 2 moles of Mg, giving:
2Mg + O2 --> 2MgO
Therefore for a stoichiometric reaction where no reactant is left over, the number of moles of magnesium must be double that of oxygen. However, as seen, the molar ratio of magnesium to oxygen is 2:5, meaning oxygen is in large excess, and Magnesium is the limiting reactant. Therefore the answer is A.
8 0
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Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or
Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

  • The oxidation number of a free element is always zero.
  • The oxidation number of a monatomic ion equals the charge of the ion.
  • The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.
  • The oxidation number of  oxygen (O)  in compounds is usually -2.
  • The oxidation number of a Group 17 element in a binary compound is -1.
  • The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
  • The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) H_2SO_4

Let the oxidation state of 'S' be, 'x'

2(+1)+x+4(-2)=0\\\\x=+6

Hence, the oxidation state of 'S' is, (+6)

(b) Ca(OH)_2

Let the oxidation state of 'Ca' be, 'x'

x+2(-2+1)=0\\\\x=+2

Hence, the oxidation state of 'Ca' is, (+2)

(c) BrOH

Let the oxidation state of 'Br' be, 'x'

x+(-2)+1=0\\\\x=+1

Hence, the oxidation state of 'Br' is, (+1)

(d) ClNO_2

Let the oxidation state of 'N' be, 'x'

-1+x+2(-2)=0\\\\x=+5

Hence, the oxidation state of 'N' is, (+5)

(e) TiCl_4

Let the oxidation state of 'Ti' be, 'x'

x+4(-1)=0\\\\x=+4

Hence, the oxidation state of 'Ti' is, (+4)

(f) NaH

Let the oxidation state of 'Na' be, 'x'

x+(-1)=0\\\\x=+1

Hence, the oxidation state of 'Na' is, (+1)

4 0
3 years ago
Calculate the mass of water produced when 1.36 g of butane reacts with excess oxygen.
ANTONII [103]

Answer:

Mass of water produced= 1.8 g

Explanation:

Given data:

Mass of water produced = ?

Mass of butane = 1.36 g

Mass of oxygen = excess

Solution:

Chemical equation:

2C₄H₁₀ +13 O₂       →   8CO₂ + 10H₂O

Number of moles of butane:

Number of moles = mass/molar mass

Number of moles = 1.36 g/ 58.12 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of butane with water.

                 C₄H₁₀         :        H₂O

                  2              :           10

                 0.02          :         10/2×0.02 = 0.1 mol

Mass of water produced:

Mass = molar mass × molar mass

Mass = 0.1 mol × 18 g/mol

Mass = 1.8 g

6 0
3 years ago
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