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Fed [463]
2 years ago
6

if the time is taken to bring a ball to rest from a certain velocity 'v'. is reduced to half, what will be the change in the val

ues of a) initial momentum b) final momentum c) rate of change of momentum?
Physics
1 answer:
777dan777 [17]2 years ago
6 0

The answer is C) rate of change of momentum. The answer is not initial or final momentum as the start and end points are not changing. On the other hand, the time it takes for the ball to change velocity is. This change relates to the change of momentum. Hope this helped :))

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Write down the kirchhoff's laws in the adjoining circuit , find the current in each resistors​
lapo4ka [179]

Answer:

You need a motor and a battery

Explanation:

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2 years ago
In a pool game, the cue ball, which has an initial speed of 3.0 m/s, make an elastic collision with the eight ball, which is ini
zhenek [66]

Explanation:

Given

initial speed(u)=3 m/s

mass of each ball is m

Let the cue ball is moving in x direction initially

In elastic collision Energy and momentum is conserved

Let u be the initial velocity and v_1 , v_2 be the final velocity of 8 ball and cue ball respectively

\frac{mu^2}{2}+0=\frac{mv^2_1}{2}+\frac{mv^2_2}{2}

The angle after which cue ball is deflected is given by

\theta _1=90-40=50^{\circ}

Conserving momentum in x direction

mu=mv_1cos40+mv_2cos50

3=v_1cos40+v_2cos50

Along Y axis

0+0=v_1sin40-v_2sin50

v_1sin40=v_2sin50

substitute the value of v_1

we get v_2=1.912 m/s

v_1=2.27 m/s

5 0
3 years ago
Short Answer
liq [111]

Answer:

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3 years ago
A car accelerates from rest for 5 seconds until it reaches a speed of 20 m/s. what is the car's acceleration in meters per secon
barxatty [35]
Acceleration = change in velocity divided by time taken...

I.e Acceleration = (Final velocity - Initial Velocity) /time taken...

The question says the body accelerate from rest... Therefore it's initial velocity = 0

It reach a speed(velocity) of 20m/s.. My final velocity

And the time taken to attain the velocity = 5 seconds....

Therefore

acceleration = (20-0)/5

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Hope this helped....
3 0
2 years ago
There is a lever. The fulcrum is 1 m from the left end, and 3 m from the right end. A block of 60 N is hung to the left end. To
yuradex [85]

Answer:

A 20 N force acting downward on the right end of the lever would keep it horizontal.

Explanation:

Recall that in order to keep the lever horizontal and without rotating, one needs the sum of the acting torques to be zero.

The torque that the 60 N force of the hanging block produces, contributes to a positive torque (according to the convention counter-clock motion is positive), and its magnitude is the product of the force times its distance to the fulcrum: 60 N * 1 m = 60 Nm.

So we need a negative torque of the same absolute magnitude from the right hand side. Then a force downward will accomplish the negative sign required (according to convention clockwise motion is negative). The magnitude of that torque should equal 60 Nm as well, so we find which force, acting at the other end (3 m from the fulcrum) would accomplish such:

60\, N\,m\,= F\,*\,3 \,m\\F=60/3 \,\,N\\F=20\,N

Therefore, a 20 N force acting downward would keep the lever horizontal.

5 0
3 years ago
Read 2 more answers
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