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Artyom0805 [142]
3 years ago
14

List the four processes in the Otto cycle.

Engineering
1 answer:
OleMash [197]3 years ago
7 0

Answer:

Explanation:

A woman walks due west on the deck of a ship at 3 miyh.The ship is moving north at a speed of 22 miyh.Find the speed and direction of the woman relative to the surface of the water.

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What is the weight density of a cylinder that has a diameter of 4.0 inches and a height of 10.0 inches? The cylinder weighs 2.0
zhannawk [14.2K]

Answer:

20

Explanation:

4.0 has the diameter of 2.0 lbs so dived it is 20

7 0
3 years ago
At a high school science fair, Connor won first place for his replica of the Golden Gate Bridge. Connor liked the project so muc
AnnZ [28]

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a

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6 0
4 years ago
What is capillary action?
BARSIC [14]
Capillary action occurs When the adhesion to the walls stronger than dirt cohesive forces between a liquid molecules. the head towards Capillery action will take water in a uniform circular is limited by surface tension and, of course, gravity.
4 0
2 years ago
In the figure below, block A weighs 20 lb , while block B weighs 10 lb . Friction between the surfaces of the two blocks may be
scoray [572]

Answer:

As P is continually increased, the block will now slip, with the friction force acting on the block being: f = muK*N, where muK is the coefficient of kinetic friction, with f remaining constant thereafter as P is increased.

8 0
3 years ago
What is the heat loss coefficient that has a symbol Uair and is found from (volumetric flow * density * specific heat capacity)
aleksley [76]

Answer:

Uair = 0.0749 KW/k = 74.9 W/k

Explanation:

The natural air change per hour is given by the formula:

Natural Air Change per Hour = ACPH = 60*Volume Flow/Volume

where,

ACPH = 0.4

Volume Flow = ? in ft³/min

Volume = 19456 ft³

Therefore,

0.4 = (60 min)(Volume Flow)/(19456 ft³)

Volume Flow = (0.4)(19456 ft³)/(60 min) = (129.7 ft³/min)(1 min/60 s)

Volume Flow =  (2.16 ft³/s)(0.3048 m/1 ft)³ = 0.061 m³/s

Now, we find heat loss coefficient:

Uair = Volumetric Flow*Density of air*Specific Heat Capacity of air

Uair = (0.061 m³/s)(1.225 kg/m³)(1 KJ/kg.k)

<u>Uair = 0.0749 KW/k = 74.9 W/k</u>

6 0
3 years ago
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