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Romashka [77]
3 years ago
7

20. All financial goals are long-term goals. True False

Physics
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

Hello todays answer should be False i am sorry if i am incorrect-Lucy

Explanation:

zalisa [80]3 years ago
8 0

Answer:

True

Explanation:

Because its facts

It will impact the rest of your career

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Far out in space, a 100,000-kg rocket and a 200,000-kg rocket are docked at opposite ends of a motionless 90m-long tunnel. The t
postnew [5]

Answer:

a) X_{cm} = 60m

b) I = 5.4*10^8Kg*m^2

c) T= 4.5*10^6 N*m

d) a = 8.3*10^{-3}rad/s^2

e) W= 0.25 rad/s

Explanation:

a) we know that:

X_{cm} = \frac{m_1x_1+m_2x_2}{m1+m2}

where X_cm is the ubicaton of the center of mass, m_1 the mass of the first rocket, x_1 its distances with the rocket 1, m_2 the mass of the second rocket and x_2 its distance with the rocket 1. So, replacing values, we get:

X_{cm} = \frac{(100,000kg)(0)+(200,000kg)(90m)}{100,000kg+200,000kg}

X_{cm} = 60m

So, the center of mass is at 60m from the rocket 1.

b) we know that:

I = M_1R_1^2 +M_2R_2^2

where I is the moment of inertia, M_1 is the mass of the rocket 1, R_1 its distance from the center of mass, M_2 the mass of the second rocket and R_2 the distance between the rocket 2 and the center of mass. So, replacing values, we get:

I = (100,000kg)(60m)^2 +(200,000kg)(30m)^2

I = 5.4*10^8Kg*m^2

c) We know that:

T = Fr

where T is the net torque, F is the force and r is the distance between the rocket and the radius. Then:

FR_1+FR_2 = T

Replacing values, we get:

50,000N(60m)+50,000N(30m) = T

T= 4.5*10^6 N*m

d) We know that:

T = Ia

where T is the net torque, I the moment of inertia and a is the angular aceleration. So, replacing values, we get:

4.5*10^6Nm = 5.4*10^8Kg*m^2a

solving for a:

a = 8.3*10^{-3}rad/s^2

e) Finally, using:

W = at

where W is the angular velocity, a is the angular aceleration and t is the time.

Then, replacing values. we get:

W = (8.3*10^{-3}rad/s^2)(30s)

W = 0.25 rad/s

3 0
3 years ago
If an electric charge is accumulated on an object, it is referred to as _____
LenaWriter [7]
Static, because it stays on the object.
3 0
3 years ago
Read 2 more answers
The airplane refuels between City A and continues on to City B. It travels at an average speed of 733.9 km/h. If the trip takes
Ronch [10]

Answer:

733.9× 2.4

1761.36

Explanation:

The airplane refuels between city A and continues on to city B. It travels at an average speed of 733.9km/h. If the trip takes 2.4 hours, what is the flight distance between city A and city B?

8 0
2 years ago
A person pushes horizontally on a 50-kg crate, causing it to accelerate from rest and slide across the surface. If the push caus
Marina CMI [18]

Answer:

v_{f} =4.9\frac{m}{s}  :  velocity of the crate after the person has pushed the crate a distance of 6 meters

Explanation:

Crate kinetics

Crate moves with uniformly accelerated movement

v f²=v₀²+2a*d (formula 1)

d:displacement in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

Known data

v₀=0 The speed of the crate is equal to zero because part of the rest.

a= 2m/s²

d= 6m

Distance calculating

We replace data in the Formula (1)

v f²=0+2*2*d

v f²=2*2*6

v f²=24

v_{f} =\sqrt{24}

v_{f} =4.9\frac{m}{s}

7 0
3 years ago
A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67
ivann1987 [24]

Answer:

6.22 N/m

Explanation:

F=xk  Making k the subject of the formula then

k=\frac {F}{x}

But since the applied force F is mg then we substitute mg with F is the formula hence

k=\frac {mg}{x}

Converting the given mass from g to Kg, we divide it by 1000 hence m= 0.425 and taking g as 9.81 and substituting x with 0.67 m then

k=\frac {0.425\times 9.81}{0.67 m}=6.222761194\ N/m\approx 6.22\ N/m

4 0
3 years ago
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