The chemical equation is:
CH₄ + 2O₂ → CO₂ + 2H₂O
First, we calculate the moles of methane present using:
Moles = mass / molecular mass
Moles = 20 / 16
Moles = 1.25
Next, we may observe from the chemical equation that the molar ratio between methane and oxygen is 1 : 2
So the moles of oxygen required are 2 x 1.25
2.5 moles of oxygen required
Mass = moles * molecular mass
Mass = 2.5 * 32
Moles = 80
C. 80 grams O₂
Answer:
397 L
Explanation:
Recall the ideal gas law:

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

The left-hand side is simply some constant. Hence, we can write that:

Substitute in known values:

Solving for <em>V</em>₂ yields:

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.
(Assuming 100 L has three significant figures.)
Answer:
to give something to that kid to eat
Explanation:
I think the correct answer from the choices listed above is the first option. When the the pressure is increased, the equilibrium of the reaction would favor <span>formation of reactants. One indication would be the gas that is present in the product side. Increasing the pressure would allow the products to react and form the reactants. Hope this helps.</span>