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sergejj [24]
3 years ago
7

Four chemical compounds labeled from A to D. Compound A is CH3NH2. Compound B is CH3SH. Compound C is CH3CH2CHO with an O atom d

ouble-bonded to the third (from left to right) carbon atom. Compound D is CH3OPO3. Two oxygen atoms that are attached to the phosphorous atom are negatively charged. Which molecule can be a result of mercaptoethanol reduction of a disulfide bridge?
Chemistry
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

Compound D is CH3OPO3 is the best answer

Explanation:

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What type of reaction always takes one large molecule and breaks it down into its smaller pieces?
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Answer:

The answer to your question is the letter D. a decomposition reaction

Explanation:

This is a brief description of the main chemical reactions.

a) A synthesis reaction is when two reactants are combined to form only one product.

b) A disynthesis reaction. I have not heard about this chemical reaction, I think it does not exist.

c) A combustion reaction is when an organic molecule reacts with oxygen to form carbon dioxide and water.

d) A decomposition reaction is when one reactant splits to form two or more products.

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7. What must you do before you make a hypothesis?
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One mole of copper equals about how many atoms?
Arlecino [84]

One mole of copper equals 6.02 × 10^23 atoms. The answer is letter C. This follows the Avogaro’s law wherein 1 mole of a substance is equal to 6.02 x 10^23 atoms, formula units or molecules. This is applicable to all substances. 

8 0
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How is radiation different from conduction?
steposvetlana [31]

Answer:

<u>Radiation is the transfer of energy by waves, and conduction is the transfer of heat through contact with air.</u>

Explanation:

Conduction is the transfer of thermal energy through direct contact.  Radiation is the transfer of thermal energy through thermal emission.

7 0
3 years ago
Calculate the standard enthalpy of formation of NOCl(g) at 25 ºC, knowing that the standard enthalpy of formation of NO(g) at th
stepan [7]

Answer:

The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol

Explanation:

The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:

Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants

In this case, you have:  2 NOCl(g) → 2 NO(g) + Cl₂(g)

So, ΔH=2*H_{NO} +H_{Cl_{2} }-2*H_{NOCl}

Knowing:

  • ΔH= 75.5 kJ/mol
  • H_{NO}= 90.25 kJ/mol
  • H_{Cl_{2} }= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound  the chlorine Cl₂)
  • H_{NOCl}=?

Replacing:

75.5 kJ/mol=2* 90.25 kJ/mol + 0 - H_{NOCl}

Solving

-H_{NOCl}=75.5 kJ/mol - 2*90.25 kJ/mol

-H_{NOCl}=-105 kJ/mol

H_{NOCl}=105 kJ/mol

<u><em>The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol</em></u>

8 0
3 years ago
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