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I am Lyosha [343]
3 years ago
7

Two toy cars (m1 = 0.200 kg and m2 = 0.250 kg) are held together rear to rear with a compressed spring between them. When they a

re released, the cars are free to roll away from the ends of the spring.
If you measure the acceleration of the 0.200-kg car to be 2.65 m/s2 to the right, what is the acceleration of the other car?
Physics
1 answer:
timurjin [86]3 years ago
8 0

Answer:

Acceleration of the second particle at that moment is given as

a_2 = 2.12 m/s^2

Explanation:

As we know that both cars are connected by same spring

So on this system of two cars there is no external force

So we will have

F = 0 = m_1a_1 + m_2a_2

now we have

m_1 = 0.200 kg

m_2 = 0.250 kg

a_1 = 2.65 m/s^2

now we have

0.200(2.65) + 0.250a_2 = 0

so we have

a_2 = 2.12 m/s^2

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<h3><u>Answer</u>;</h3>

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<h3><u>Explanation</u>;</h3>
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"Non nobis, Domine, non nobis, sed Nomini tuo da gloriam."


Regards M.Y.
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