Answer:
The maximum height above the point of release is 11.653 m.
Explanation:
Given that,
Mass of block = 0.221 kg
Spring constant k = 5365 N/m
Distance x = 0.097 m
We need to calculate the height
Using stored energy in spring
...(I)
Using gravitational potential energy
....(II)
Using energy of conservation




Where, k = spring constant
m = mass of the block
x = distance
g = acceleration due to gravity
Put the value in the equation


Hence, The maximum height above the point of release is 11.653 m.
<span>v = 25.0 km/</span><span>h = 25*5/18 m/s = 6.94 m/s
</span><span>centripetal force = mv²/r = 1275*6.94²/40 = 1537.18 N </span>
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.
Divide the distance traveled by the time it took:
(100 m) / (4.2 s) ≈ 23.8 m/s
Answer:
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Explanation: