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3 years ago

HELP!!!

Physics

1 answer:

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

Explanation:

A is not correct. That means that D is since they offer exactly the opposite meanings.

C is rubbish. One pole could not be stronger than the other. Heaven help us if touched the stronger pole.

B the very point of a magnet is that it does matter how the atoms are orientated.

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The reciprocal of frequency is

Colt1911 [192]

Frequency=1/T, where T is the time period.
Reciprocal of frequency = T or it can be written as T = 1/f, where f is frequency.

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3 years ago

What is the total capacitance in units of mF, of the two capacitors connected in series, as shown in the diagram, when C1 = 45 m

elena-14-01-66 [18.8K]

Answer:

16.7 mF

Explanation:

The total capacitance of two capacitors connected in series is given by the formula:

$\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}$

in our problem, we have:

C1 = 45 mF is the capacitance of the first capacitor

C2 = 26 mF is the capacitance of the second capacitor

Substituting into the equation, we find:

$\frac{1}{C}=\frac{1}{45 mF}+\frac{1}{26 mF}=0.06 mF^{-1}\\C=\frac{1}{0.06 mF^{-1}}=16.7 mF$

7 0

3 years ago

Read 2 more answers

Electrons of wavelength 1.5 nm are emitted from a material when light of wavelength 350nm is incident on it. What is the work fu

krok68 [10]

Answer:

3.5434 eV

Explanation:

For a particle with kinetic energy E and mass m , the wavelength associated is given by the following relation,

$\lambda=\frac{h}{\sqrt{2mE} }$

E = $\frac{h^2}{2m\lambda^2}$

Putting the values we get

E = $\frac{(6.6\times(10^{-34})^2}{2\times9.1\times10^{-31\times(1.5\times10^{-9})^2}}$

=1.063 x 10⁻²¹ J

= .0066 eV.

Energy of¹light in terms of eV

= 1244 / 350 = 3.55 eV.

Work function = 3.55 - 0.0066 = 3.5434 eV.

7 0

4 years ago

A soccer goal is 2.44 m high. A player kicks the ball at a distance 13 m from the goal at an angle of 40°, and the ball just hit

Vera_Pavlovna [14]

Let v denote the initial speed of the ball. The ball's position at time t is given by the vector

$\mathbf r(t)=v\cos40^\circ\,t\,\mathbf i+\left(v\sin40^\circ\,t-\dfrac g2t^2\right)\,\mathbf j$

where g is the acceleration due to gravity with magnitude 9.80 m/s^2.

The ball reaches the goal 13 m away at time t such that

$10\,\mathrm m=v\cos40^\circ t\implies t=\dfrac{10\,\mathrm m}{v\cos40^\circ}$

at which point it attains a height of 2.44 m, so that

$2.44\,\mathrm m=v\sin40^\circ\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)-\dfrac g2\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)^2$

$2.44\,\mathrm m=(10\,\mathrm m)\tan40^\circ-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)\left(\dfrac{100\,\mathrm m^2}{v^2\cos^240^\circ}\right)$

$\implies\boxed{v\approx3.75\dfrac{\rm m}{\rm s}}$

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4 years ago

Bone with a latticework structure is called

malfutka [58]

Spongy or the cancellous bone is the bone with lattice work structure

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3 years ago