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Studentka2010 [4]
2 years ago
8

A 15.0 kg medicine ball is thrown at a velocity of 10.0 m/s to a 60.0 kg person who is a rest on ice. The person catches the bal

l and immediately slides across the ice. Assume that momentum is conserved and there is no friction. Calculate the velocity of the person AND THE BALL.
Physics
2 answers:
shutvik [7]2 years ago
7 0

Answer:

The velocity of ball and man after catching ball is 2m/s

Explanation:

Since there is no friction and no external force the momentum is conserved .

Here when man catches ball then man and ball move with common velocity .

Let the final common velocity be v_{f},

     Given  that  mass of the ball is  m_{b} =15kg

    Given  that mass of man is m=60kg

  Initial velocity of ball = v_{i} = 10m/s

Now considering momentum conservation

             p_{i} =p_{f}

     m_{b}v_{i} = (m_{b} +m)\times v\\v=m_{b}v_{i}/(m_{b} +m) = \frac{150}{75} =2m/s

Alexxandr [17]2 years ago
7 0

Answer:

Ball = 150kg*m/s

Explanation:

How to find momentum, p:

p = m*v    (P=MOMENTUM, M=MASS, V=VELOCITY OF BALL)

P = 15*10

P=150

For the human, momentum is always conserved, so what the momentum is before the ball is thrown must equal after the ball is thrown:

pBEFORE= pAFTER

mv = mv

(15)(10) = (60)(v)    SOLVE FOR V

150 = 60v

v = 5/3

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8 0
3 years ago
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