Answer:
a =( -0.32 i ^ - 2,697 j ^) m/s²
Explanation:
This problem is an exercise of movement in two dimensions, the best way to solve it is to decompose the terms and work each axis independently.
Break down the speeds in two moments
initial
v₀ₓ = v₀ cos θ
v₀ₓ = 5.25 cos 35.5
v₀ₓ = 4.27 m / s
= v₀ sin θ
= 5.25 sin35.5
= 3.05 m / s
Final
vₓ = 6.03 cos (-56.7)
vₓ = 3.31 m / s
= v₀ sin θ
= 6.03 sin (-56.7)
= -5.04 m / s
Having the speeds and the time, we can use the definition of average acceleration that is the change of speed in the time order
a = ( - v₀) /t
aₓ = (3.31 -4.27)/3
aₓ = -0.32 m/s²
= (-5.04-3.05)/3
= -2.697 m/s²
When you catch the ball you act surprised, action- reaction
Answer:
The volume at the surface is 10.97 L.
Explanation:
Given that,
Volume = 5.5 L
Height = 10 m
Density of sea water= 1025 kg/m³
We need to calculate the pressure at that point
Using formula of pressure
Put the value into the formula
We need to calculate the volume at the surface
Using equation of ideal gas
So, for both condition
Put the value into the formula
Hence, The volume at the surface is 10.97 L.