Answer:
T = 2010 N
Explanation:
m = mass of the uniform beam = 150 kg
Force of gravity acting on the beam at its center is given as
W = mg
W = 150 x 9.8
W = 1470 N
T = Tension force in the wire
θ = angle made by the wire with the horizontal = 47° deg
L = length of the beam
From the figure,
AC = L
BC = L/2
From the figure, using equilibrium of torque about point C
T (AC) Sin47 = W (BC)
T L Sin47 = W (L/2)
T Sin47 = W/2
T Sin47 = 1470
T = 2010 N
static electricity and friction
The formula for getting the distance will be distance = speed x time
D = S x T
speed or velocity = 50km/h
time = 0.5 h
the equation will be done directly because it's already in it's SI units
distance = 50km/h x 0.5h
hour cancels hour and the equation remains = 50km x 0.5
Ans = 25 km
the train will move 25 km far in 0.5h
Answer:
32 m/s
Explanation:
The speed of a bus is 30 m/s due East wrt the passenger
He also sees a passenger on the bus walking to the back at 2 m/s.
We need to find the passenger's velocity relative to the bus. As the observer sees that the bus and the passenger are moving in opposite direction. Let v is the relative velocity. So,
v = 30 m/s + 2 m/s
v = 32 m/s
Hence, the passenger's velocity relative to the bus is 32 m/s.
Answer:
a = 2.44 m/s²
Explanation:
The Net force acting on the car downwards the plane will be equal to the component of the weight that is parallel to the plane.
Thus;
mg(sin θ) = ma
Thus;. g(sin θ) = a
g is acceleration due to gravity = 9.81 m/s²
θ = 14.4°
Thus;
9.81 × sin 14.4 = a
a = 2.44 m/s²
