A + 3A = 120
4A = 120
A = 30
B = 90
let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.
cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.
F(x) = 2/3x + 1
This is in the slope-intercept form of an equation for a line.
Which is written as this: (Note f(x)= is the same as saying y= in this case)
y = mx + b
M is our slope. Slope is the RISE over the RUN
In other words it is y/x
For this graph y represents distance, and x represents time. (Life Tip: TIME is almost ALWAYS the X value)
In this case M = 2/3
So her speed is:
2 units/3 units
B is the y-intercept. The y-intercept is where the X-value equals 0. So, (0,y). Because the y-intercept is distance she should have a y-intercept of 0. (The origin) because that would mean at the start of the race she had no distance (aka she was at the starting line).
Because her y-intercept (b) = 1 she did have a head start.
Here are both the answers at once to make it easier for you:
Speed (Replace Units with whatever units you were given. Distance Units go on top. Time units on bottom. Example: Meters/Second))
2 units/3 units
Did she have a head start? (Unit being whatever distance unit you were given)
Yes, 1 unit.
S=16t^2
if t=3
So you would plug it in
16(3)^2
Then you multipy
16*3^2
=144
It is easier if you use a calculator just type in ti 30 calculator online that should help
