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atroni [7]
3 years ago
7

Two identical stones are thrown from the top of a tall building. Stone 1 is thrown vertically downward with an initial speed v,

and stone 2 is thrown vertically upward with the same initial speed. Neglecting air resistance, how do their speeds compare on hitting the ground?
Physics
1 answer:
Molodets [167]3 years ago
5 0

If the resistance of the Air is ignored, we can use the theory given by Galileo in which he warned that the thermal velocity of a body in free fall was given by

v= \frac{1}{2}gt

Where

g = Gravitational acceleration

t = time

As we can see the speed of objects in free fall is indifferent to the position that is launched (as long as the resistance of the air is ignored) or its mass.

Both bodies will end with the same thermal speed.

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Find the ratio of the gravitational force between two planets if the masses of both planets are quadrupled but the distance betw
Snezhnost [94]

Answer:

The ratio of the new force over the original force is 16

Explanation:

Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:

F_G=G\,\frac{M_1\,\,M_2}{D^2}

So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:

F'_G=G\,\frac{4M_1\,\,4M_2}{D^2}=G\,\frac{16\,\,M_1\,\,M_2}{D^2}=16\,\,G\,\frac{M_1\,\,M_2}{D^2}= 16\,\,F_G

which is 16 times the original force.

So the ratio of the new force over the original force is 16

5 0
3 years ago
A mercury thermometer is constructed as
Tamiku [17]

Answer:

The change in height of the mercury is approximately  2.981 cm

Explanation:

Recall that the formula for thermal expansion in volume is:

\frac{\Delta V}{V_0} =\alpha_V\, \Delta\, T\\\Delta V = V_0\,\, \alpha_V\,\,\Delta C

from which we solved for the change in volume \Delta V due to a given change in temperature \Delta T

We can estimate the initial volume of the mercury in the spherical bulb of diameter 0.24 cm ( radius R = 0.12 cm) using the formula for the volume of a sphere:

V_0=\frac{4}{3} \pi \, R^3\\V_0=\frac{4}{3} \pi \, (0.12\,cm)^3\\V_0=0.007238\,cm^3

Therefore, the change in volume with a change in temperature of 36°C becomes:

\Delta V = V_0\,\, \alpha_V\,\,\Delta C\\\Delta V = 0.007238229\, cm^3\,(0.000182)\,(36)\\\Delta V=0.0000474248\, cm^3

Now, we can use this difference in volume, to estimate the height of the cylinder of mercury with diameter 0.0045 cm (radius r= 0.00225 cm):

V_{cyl}=\pi r^2\,h\\h =\frac{V_{cyl}}{\pi r^2} \\h=\frac{0.0000474248\, cm^3}{\pi \, (0.00225\,cm)^2} \\h=2.98188 \,cm

8 0
3 years ago
Three capacitors are connected as follows: 2.8 F capacitor and 5.57 F capacitor are connected in series, then that combination i
DedPeter [7]

ANSWER

8.99 F

EXPLANATION

We know that two capacitors of capacitances 2.8 F and 5.57 F are connected in series, while a third capacitor of capacitance 7.13 F is connected in parallel to that combination,

The capacitance works similarly to the resistance, except that when capacitors are connected in parallel, their capacitances add up, while when they are connected in series, the equivalent capacitance is like we were finding the equivalent resistance of resistors connected in parallel,

C_{eq}=\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}+C_3=\frac{1}{\frac{1}{2.8F}+\frac{1}{5.57F}}+7.13F\approx8.99F

Hence, the total capacitance is 8.99 F, rounded to the nearest hundredth.

6 0
2 years ago
What is the cheetah's average speed for the first 3.11 s of its sprint? for the second 3.11 s of its sprint?
photoshop1234 [79]
<span>when you say a=4.02 i am going to acceleration in m/s^2. If the acceleration is 4.02 then you take the integral to find the speed. speed=4.02 t where t is time in seconds. [4.02(0)+4.02(3.11)]/2=6.2511 [4.02(3.11)+4.02(6.22)]/2=18.7533</span>
5 0
3 years ago
A jet begins a flight along a path due north at 300 miles per hour. A wind is blowing due west at 30 miles per hour. Find the re
schepotkina [342]

Answer:

about 301 mph 5.7 west of north

Explanation:

6 0
2 years ago
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