Answer:
Explanation:
θ( p ) + θ( r ) = 90
θ (r) = angle of refraction and θ ( p ) is polarising angle.
given θ ( r ) = 31.8
θ ( p ) = 90 - 31.8 = 58.2 degree
ii ) Tanθ ( p ) = n ( refractive index ) = Tan 58.2 = 1.6
Answer:
41.74 m/s
Explanation:
The energy used to draw the bowstring = the kinetic energy of the arrow.
Fd = 1/2mv²................................ Equation 1
Where F = force, d = distance move string, m = mass of the arrow, v = speed of the arrow.
make v the subject of the equation
v = √(2Fd/m)...................... Equation 2
Given: F = 201 N, m = 0.3 kg, d = 1.3 m.
Substitute into equation 2
v = √(2×201×1.3/0.3)
v = √(1742)
v = 41.74 m/s.
Hence the arrow leave the bow with a speed of 41.74 m/s
Water filters and internet to get more knowledge
55 Kg has a weight of 55x9.8= 539 N
That is equal to the Normal force.
The static friction = 0.19 x 539 = 102.4 N
Temperature, The highness, and the time.
Hope this helps!
C=