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Mashutka [201]
2 years ago
11

The more impressive the tail of a male peacock, the higher its chances of finding a mate. Female peacocks choose mates based on

the color of the feathers and the overall physical prowess of the animal. However, a genetic mutation called leucism can produce a peacock with only white feathers. This mutation causes the inability of pigment to be deposited into their feathers which results in a white appearance. What would you infer to be the fitness of the white peacock? Choose ALL that apply.
A) The females will equally choose the brightly colored and white peacocks as mates.
B) White peacocks are highly prized, thought to symbolize purity, eternity, and unconditional love, making them desirable mates.
C) If females choose the brightest males as partners, the ones without the impressive tails will be less likely to mate and reproduce.
D) White peacocks are highly prized, thought to symbolize purity, eternity, and unconditional love, causing them to be selectively bred for their unique trait.
E) The peacocks with colored tails will be picked over the white peacocks as mates, causing the peacocks with the white mutation to die out of the population over time
Chemistry
1 answer:
Kipish [7]2 years ago
5 0

C i took the test and got it correct

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In animals, nitrogenous wastes are produced mostly from the catabolism of _____. In animals, nitrogenous wastes are produced mos
RoseWind [281]

Answer:

Proteins and nucleic acids

Explanation:

Nitrogen compounds in animals that are no longer of use, or are in access are excreted from the animals body, and are thus called nitrogenous waste. These nitrogenous waste can be excreted in three different ways.

1. Ammonia

2. Urea

3. Uric acid

8 0
3 years ago
what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

5 0
3 years ago
What type of sugar has the largest surface area
Valentin [98]

Answer:

d.) granulated

Because the granulated sugar has a greater surface area.

7 0
3 years ago
The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?
Aloiza [94]

Answer:

0.0468 g.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

<em>∴ (a-x) = 12/256.34 = 0.0468 g.</em>

8 0
3 years ago
Which organisms are consumers?
masya89 [10]

Answer: snake grass hopper and monkey

Explanation: i took the test and this is what i got

8 0
2 years ago
Read 2 more answers
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