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ANTONII [103]
3 years ago
11

Tech A says that when cleaning brake and clutch components, the wash station should be placed directly under the component. Tech

B says that you should follow state and local regulations when disposing of used oil. Who is correct
Engineering
1 answer:
nika2105 [10]3 years ago
4 0

Both of the Technicians are correct because both advice need to be followed by the car owner.

<h3>Who are the Technicians?</h3>

The technicians are people who are expertise in automotive repair, that is, they work with mechanical systems and equipment to make sure the cars run well.

In conclusion, both of the Technicians are correct because both advice need to be followed by the car owner.

Read more about Technicians

<em>brainly.com/question/25744725</em>

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Write an expression for the output voltage of an AC source that has an amplitude of 19 V and a frequency of 240 Hz. (Use the fol
Umnica [9.8K]

Answer:

Expression for output voltage =  V = Vo sin wt

Explanation:

Amplitude of output voltage = Vo = 19 V

Frequency = f = 240 Hz

Now we know that

Angular frequency = w = 2 π (1 / T) = 2  π 240 = 480 π Hz

Expression for output voltage =  V = Vo sin wt

Expression for output voltage =  V = 19 (sin 480 π) t

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ahrayia [7]

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a clock

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If coolant is mixed 50-50 with water, what is the freezing point?
sashaice [31]

Answer:

-35 degrees F

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3 years ago
A wood pipe having an inner diameter of 3 ft. is bound together using steel hoops having a cross sectional area of 0.2 in^2. The
Minchanka [31]

Answers:

31.7 inches

Explanation:

Given:

Diameter = 3ft

Let D = Diameter

So, D = 3ft. (Convert to inches)

D = 3 * 12in = 36 inches

Coss-sectional area of the steel = 0.2in²

Gauge Pressure (P) = 4psi

Stress in Steel (σ)= 11.4ksi

Force in steel = ½ (Pressure * Projected Area)

Area (A) = 2 * Force/Pressure

Also, Area (A) = Spacing (S) * Wood Pipe Diameter

Area = Area

2*Force/Pressure = Spacing * Diameter

Substitute values I to the above expression

2 * Force / 4psi = S * 36 inches

Also

Force in steel (F) = Stress in steel (σ) × Cross-sectional area of the steel

So, F = 11.4ksi * 0.2in²

F = 11.4 * 10³psi * 0.2in²

F = 2.28 * 10³ psi.in²

So, 2 * Force / 4psi = S * 36 becomes

2 * 2.28 * 10³/4 = S * 36

S = 2 * 2.28 * 10³ / (4 * 36)

S = 4560/144

S = 31.66667 inches

S = 31.7 inches (approximated)

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please make brainlist

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