R 1,2 = 27.5 + 33.0 = 60.5 Ohms
1/ R 1,2,3 = 1/ 60.5 + 1 / 22 = 82.5 / 1331
R 1, 2, 3 = 1331 / 82.5 = 16.13 Ohms
I = U / R
I = 9 V / 16.13 Ohms = 0.557 A ≈ 0.56 A
Answer: C ) 0.56 Amps
Answer:
The inductance of the inductor is 35.8 mH
Explanation:
Given that,
Voltage = 120-V
Frequency = 1000 Hz
Capacitor 
Current = 0.680 A
We need to calculate the inductance of the inductor
Using formula of current
Put the value of Z into the formula
Put the value into the formula
Hence, The inductance of the inductor is 35.8 mH
Q=mc(t2-t1)
Q=2.06kg x specific heat of oil(191-23)
Q=2.06×c×168
Q=143.62q
Answer:
A. The number of valence electrons increases by 1.
Explanation:
As you move across any period on the periodic table, the number of valence electrons increases by a value of 1.
- The periodic table of elements contains an arrangement of element by their atomic numbers.
- From left to right, number of valence electrons increases.
- Down a group, the valence electrons are the same.
- Across a period, the number of valence electrons increases.
