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zheka24 [161]
2 years ago
12

________ Is a push or pull

Physics
1 answer:
victus00 [196]2 years ago
5 0

Answer:

lever

Explanation:

because you can push and pull a lever

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Please help u guys acellus sucks
34kurt

Answer:

6.0cm

Explanation:

Given

focal length = 15.0cm

object distance = 10.0cm

Required

Image distance v

Using the formula

1/f = 1/u + 1/v

1/15 = 1/10+1/v

1/v = 1/15 + 1/10

1/v = 2+3/30

1/v = 5/30

v = 30/5

v = 6.0cm

Hence the image distance is 6.0cm

7 0
3 years ago
A power station burns 75 kilograms of coal per second. Each kg of coal contains 27 million joules of energy.
olasank [31]
A) P = 75 \times (2.7\times10^7) = 2.025\times10^9 W

b) Efficiency =  \frac{8\times10^8}{2.025\times10^9} \times 100 \approx 39.5\%
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3 years ago
Read 2 more answers
A wildlife photographer uses a moderate telephoto lens of focal length 135 mm and maximum aperture f/4.00 to photograph a bear t
labwork [276]

Answer:

<h3>(A) The width x = 0.24 \times 10^{-3} m</h3><h3>(B) The new width is 1.32 \times 10^{-3} m</h3>

Explanation:

Given :

Focal length f =   135 \times 10^{-3}  m

Maximum aperture D = \frac{f}{4}

Wavelength \lambda = 550 \times 10^{-9} m

(A)

From rayleigh criterion,

  \theta = \frac{1.22 \lambda }{D}

  \theta =\frac{ 1.22 \times 550 \times 10^{-9}  }{33.75 \times 10^{-3} }

  \theta = 1.98 \times 10^{-5} rad

From angle formula,

  x = R\theta

Where R = 12 m ( given in example )

x = 12 \times 1.98 \times 10^{-5} m

x = 23.76 \times 10^{-5}

x = 0.24 \times 10^{-3} m

(B)

We know that \theta is proportional to the x and inversely proportional to the D

so we write the new width, here x is 5.5 times larger than above case

   x = 0.24 \times  10^{-3}  \times \frac{22}{4}

   x = 1.32 \times 10^{-3} m

6 0
3 years ago
The high school tennis team is made up of boys and girls. The team has a total of 25 players. 8 of the players are girls. If a p
vekshin1
Probability of it being a boy is 17/25 which is .68
4 0
4 years ago
Can earthquakes with a magnitude between 3.0 and 6.0 produce high intensity levels?
Dmitry [639]
Yes if you need to know why i will tell you why
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3 years ago
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