This answer is X=-4
Work shown in the picture
Answer:
4.806 g ≤ n ≤ 5.194 where n is the mass of a nickle.
Step-by-step explanation:
The problem tells us the weight can vary by .194 g, this means it can be up to .194 lighter and 194 heavier. Well what value is .194 lighter and .194 heavier? 4.806 and 5.194 respectively. So that means a nickle can be anywhere in that range, which tells us the inequality.
Answer:

Step-by-step explanation:

Answer:
The arc length of the partial circle is 
Step-by-step explanation:
we know that
The circumference of a circle is equal to

In this problem we have a 3/4 of a circle
so
the circumference is equal to


we have

substitute


Answer:
4
Step-by-step explanation:
Is that a log with the base of 3√(2) ?
If so....my calculator says the answer is 4
Let's see if we can do it w/ou the calculator:
3 sqrt(2)^x = 324 = 3^4 * 2^2 Now 'LOG' both sides:
x log (3 sqrt 2) = log (3^4 *2^2) = 4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)
now divide both sides by log (3 sqrt2 )
x = 4 (If I did the math correctly ! )