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liberstina [14]
3 years ago
10

Solve 3(4 – x) ≤ 54

Mathematics
1 answer:
algol133 years ago
7 0
3(4 - x) <= 54

12 - 3x <= 54
-3x <= 42

x >= -14  answer

Its A
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HELLLLPPPP ME OUUT PLLLSDDEE
Allisa [31]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
What is the perimeter of triangle DEF?
Vikki [24]

Given:

Triangle DEF

To find:

The perimeter of triangle DEF.

Solution:

Coordinate of D = (-1, 1)

Coordinate of E = (2, 1)

Coordinate of F = (-1, 4)

Distance formula:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

<u>Distance of DE:</u>

Here, x_1=-1, y_1=1, x_2=2, y_2=1

d=\sqrt{(1-1)^2+(2-(-1))^2}

d=\sqrt{0+9}

d = 3 units

<u>Distance of EF:</u>

Here, x_1=2, y_1=1, x_2=-1, y_2=4

d=\sqrt{(4-1)^2+(-1-2)^2}

d=\sqrt{9+9}

d=\sqrt{18}

d = 4.2 units

<u>Distance of FD:</u>

Here, x_1=-1, y_1=4, x_2=-1, y_2=1

d=\sqrt{(1-4)^2+(-1-(-1))^2}

d=\sqrt{9+0}

d = 3 units

Perimeter of ΔDEF = DE + FE + FD

                                = 3 + 4.2 + 3

                                = 10.2 units

The perimeter of triangle DEF is 10.2 units.

5 0
3 years ago
Micah was asked to add the following expressions: 3x2−x−9x2+3x+2+−2x2+2x+5x2+3x+2 First, he combined like terms in the numerator
Natalka [10]

Micah was asked to add the following expressions:

\frac{3x^2-x-9}{x^2+3x+2} + \frac{-2x^2+2x+5}{x^2+3x+2}

First, he combined like terms in the numerator and kept the common denominator

First step is correct. He added the like terms in the numerator, because the denominators are same.

3x^2 -x -9 -2x^2+2x+5 becomes x^2 +x -4

So he got , \frac{x^2+x-4}{x^2+3x+2}

In the next step, he cannot cancel out x^2 from the top and bottom . Because x-4 and 3x+2  are added with x^2

If we have x^2 is multiplied with other terms at the top and bottom , then we can cancel out x^2.

So Micah added the expression incorrectly. Final answer is not correct.

5 0
2 years ago
Let f(x)=2x^2-x-1 and let g(x)=x-1 Which statement is true?​
sergij07 [2.7K]

Answer:

B is true

Step-by-step explanation:

given f(x) = 2x² - x - 1 and g(x) = x - 1

A

If x = - 1 is a root then f(- 1) = 0

f(- 1) = 2(- 1)² - (- 1) - 1 = 2 + 1 - 1 = 2 ≠ 0 ← False

B

If (x - 1) is a factor then x = 1 is a root and f(1) = 0

f(1) = 2(1)² - 1 - 1 = 2 - 1 - 1 = 0

⇒ g(x) = x - 1 is a factor of f(x) ← True

C

If x = 2 is a root then f(2) = 0

f(2) = 2(2)² - 2 - 1 = 8 - 3 = 5 ≠ 0 ← False

D

\frac{x2x^2-x-1}{x-1} = \frac{(2x+1)(x-1)}{x-1}

Cancel the factor (x - 1) on the numerator/ denominator, leaving

\frac{f(x)}{g(x)} = 2x + 1 with remainder 0 ≠ 2 ← False

7 0
3 years ago
The accounting records of Blossom Company show the following data. Beginning inventory 3,090 units at $5 Purchases 7,930 units a
meriva

Answer:

The cost of goods sold is 65,850

Step-by-step explanation:

FIFO Perpetual chart is attached.

FIFO Perpetual chart shows purchases, sales and balance of  the period.

The cost of goods sold is:

3,090 units x $5=$15,450

6,300 units x $8=$50,400

Total=65,850

Download xlsx
6 0
3 years ago
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