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Kay [80]
2 years ago
10

An ammonia solution has a pH of 8.25. What is its [OH-]?

Chemistry
1 answer:
Olegator [25]2 years ago
4 0

pH + pOH = 14

If pH=8.25, then:

pOH = 14 - 8.25 = 5.75

pOH = -log[OH-]

5.75 = -log[OH-]

-5.75 = log[OH-]

10^(-5.75) = [OH-]

[OH-] = 0,0000017783

[OH-] = 1,78×10^(-6) mol/dm³

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The pH of a neutral aqueous solution at 37°C is 6.8.

<h3>What is Kw? </h3>

Kw is defined as the dissociation, which is also known as self-ionization, constant of water. this is an equilibrium constant, and its expression is:

Kw = [OH⁻] . [H₃O⁺]

Neutral pH determines that the concentrations of OH⁻ and H₃O⁺ are equal.

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Let us suppose concentration of OH and H₃O⁺ is x, to calculate it:

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pH = 6.8

Thus, we find that the pH of a neutral aqueous solution at 37 °c (which is the normal human body temperature) is 6.8.

learn more about pH:

brainly.com/question/9529394

#SPJ4

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