All categories

2 years ago

How many band is the parametric microphone equalizer?

Physics

1 answer:

Rus_ich [418]2 years ago

8 0

Answer:

3 bands

Explanation:

Basically, the Parametric EQ divides the audio spectrum into three bands, allowing you to enhance (or suppress) the level in that range.

You might be interested in

1. Where are stars formed?

Ugo [173]

$\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}$

C. A nebula.

thanks
hope it helps

3 0

3 years ago

Read 2 more answers

1. What is the difference between longitudinal and transverse waves? Compare and contrast

Anvisha [2.4K]

Answer: image to much to type.

Explanation:

8 0

3 years ago

Which statements are part of the safety protocol for this lab experiment? Check all that apply:

vagabundo [1.1K]

Answer:

Always wear a lab coat and safety goggles when performing an experiment

7 0

2 years ago

About how many electrons are in 30 grams of water (H2O)?

jarptica [38.1K]

Hydrogen (H) has a molar mass of about 1.007 g/mol and has 1 electron.

Oxygen (O) has a molar mass of about 15.999 g/mol and has 8 electrons.

Then water (H₂O) has a total molar mass of about 18.015 g/mol and has 10 electrons.

30 g of water is the mass of

(30 g) × (1/18.015 mol/g) ≈ 1.66528 mol

of water. Recall that 1 mole is around 6.022 × 10²³ molecules (i.e. Avogadro's number). So 30 g of water is the mass of approximately 1.00285 × 10²⁴ molecules of water.

If each molecule contains 10 electrons, then 30 g of water contains 1.00285 × 10²⁵ ≈ 10²⁵ electrons.

5 0

3 years ago

A lowly high diver pushes off horizontally with a speed of 2.00 m/s from the platform edge 10.0 m above the surface of the water

VladimirAG [237]

Answer:

(a) 1.6m

(b) 6.86m

Explanation:

This is a horizontal shooting problem, so we will use the following equations.

For horizontal distance x we use:

$x(t)=x_{0}+v_{0}t$

Where $x(t)$ is the horizontal distance at a time $t$ , $x_{0}$ is the initial horizontal position which in this case will be zero: $x_{0}=0$ . And $v_{0}$ is the initial speed: $v_{0}=2m/s$

So to solve (a):

(a) At what horizontal distance from the edge is the diver 0.800 s after pushing off?

we have that the time is: $t=0.8s$ so the horizontal distance is:

$x(0.8)=(2m/s)(0.8s)1.6m$

The answer for (a) is 1.6m

Now, to solve (b) we need the equation for vertical distance:

$y(t)=y_{0}-\frac{1}{2}gt^2$

Where $y(t)$ is the vertical distance at a time $t$ , $y_{0}$ is the initial vertical distance: $y_{0}=10m$ And $g$ is the gravitational acceleration: $g=9.81m/s^2$ }