What is the only force that can act on an object in free fall?

If an element gives away an electron, will it form a positive ion or a negative<br> ion?

Elan Coil [88]

Answer:

posotive

Explanation:

electrons give off negative pulse so take one away

8 0

3 years ago

1

Molodets [167]

Answer: The temperature does effect the growth of the plants. If you kept them all at different temperature and the growth was different then the temperature is definitly a factor in plant growth

Explanation:

7 0

3 years ago

When an object is lifted 6 meters off the ground, it gains a certain amount of potential energy. If the same object is lifted 18

AlexFokin [52]

Answer:

The answer to your question is the letter C. three times as much

Explanation:

Data

First step = 6 m

Second step = 18 m

Potential energy is the energy stored that depends on its position.

Formula

Pe = mgh

m = mass; g = gravity; h = height

Potential energy of the first step

Pe1 = 6mg

Potential energy of the second step

Pe2 = 18mg

-Divide the Pe2 by the Pe1

Pe2/Pe1 = 18mg/6mg

= 3

7 0

3 years ago

How many bonding and non-bonding electron pairs are found in the BF3 molecule?

Contact [7]

Answer:

MARK AS BRAINLIEST

Explanation:

Boron trifluoride only has six valence electrons and is one of the relatively rare second period covalent molecules that disobeys the octet rule. There are three bonded groups and so no lone pairs. Six electrons implies three electron pairs and therefore a trigonal geometry.

8 0

3 years ago

Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

$CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O$

Number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 2

Number of atoms present on product side are as follows.

C = 1
H = 2
O = 3

To balance this equation, multiply $O_{2}$ by 2 on reactant side. Also, multiply $H_{2}O$ by 2 on product side. Hence, the equation can be rewritten as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

Now, the number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 4

Number of atoms present on product side are as follows.

C = 1
H = 4
O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

4 0

3 years ago