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3 years ago

Explain how by having bright and colorful flowers help plant in reproduction

1 answer:

3 0

This attracts bees which, when collecting the nectar, they carry residue pollen on the flower to the next flower, which then pollinates the flowers, hence allowing them to asexually reproduce.

You might be interested in

What characteristics do atoms of carbon-12, carbon-13, and carbon-14 have in common?

Sophie [7]

Their proton and electron numbers are same

7 0

3 years ago

A current theory states during Earth’s formation, it was struck by a planet approximately the same size as Mars. Select the foll

Ivanshal [37]

Answer:

the earth gained mass from the impact :)

welcome

7 0

2 years ago

A mixture of gaseous sulfur dioxide and oxygen are added to a reaction vessel and heated to 1000 K where they react to form SO3

nasty-shy [4]

Answer:

$Kp = 0.0410$

Explanation:

The reaction of gaseous sulfur dioxide and oxygen to form SO3 (g) is:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kp is defined as the ratio of pressure of products and pressure of reactants:

$Kp = \frac{P_{SO_3}^2}{P_{SO_2}^2P_{O_2}}$

$Kp = \frac{0.0851atm^2}{0.669atm^2*0.395atm}$

$Kp = 0.0410$

I hope it helps!

5 0

3 years ago

During studies of the following reaction (i), a chemical engineer measured a less-than-expected yield of N2 and discovered that

bonufazy [111]

Answer:

Maximum expected yield = 87.2%

Explanation:

Equations of reactions:

Main reaction: N₂O₄(l) + 2N₂H₄(l) ---> 3N₂(g) + 4H₂O(g)

Side reaction: 2N₂O₄(l) + N₂H₄(l) ----> 6NO(g) + 2H₂O(g)

Molar mass of N₂O₄ = 92 g/mol; molar mass of N₂H₄ = 32 g/mol; molar mass of N₂ = 28 g/mol; molar mass of of NO = 30 g/mol; molar mass of water = 18 g/mol

In the main reaction, 92 g of N₂O₄ reacts with 2 * 32 g of N₂H₄ to produce 3 * 14 g of N₂.

101.1 g of N₂O₄ will react with 2 * 32 * 101.1 / 92 g of N₂H₄ = 70.33 g of N₂H₄

<em>N₂O₄ is the limiting reactant</em>

101.1 g of N₂O₄ will react to produce 3 * 14 * 101.1 / 92 g of N₂ = 46.15 g of N₂

In the side reaction, (6 * 30 g) of NO is produced from (2 * 92 g) of N₂O₄ and 32 g of N₂H₄

12.7 g of N₂O₄ will be produced from ( 2 * 92 * 12.7/180 g) of N₂O₄ and (32 * 12.7/180) g of N₂H₄ to produce

mass of N₂O₄ used = 12.98 g

mass of N₂H₄ used = 2.26 g

mass of N₂O₄ left for main reaction = 101.1 - 12.98 = 88.12 g

mass of N₂H₄ left for main reaction = 101.1 - 2.26 = 98.84 g

In the main reaction, 92 g of N₂O₄ reacts with 2 * 32 g of N₂H₄ to produce 3 * 14 g of N₂

88.12 g of N₂O₄ will react with 2 * 32 * 88.12 / 92 g of N₂H₄ = 61.30 g of N₂H₄

N₂O₄ is the limiting reactant.

88.12 g of N₂O₄ will to react produce 3 * 14 * 88.12 / 92 g of N₂ = 40.23 g of N₂

Percentage yield = (theoretical yield/actual yield) * 100%

Percentage yield = (40.23/46.15) * 100% = 87.2%

Therefore, maximum expected yield = 87.2%

4 0

2 years ago

White wash suspension, a saturated solution of ca(oh)2, has a ph of 12.37. what is ksp for ca(oh)2?

SSSSS [86.1K]

Find the $pOH$ from $pH$

$pH + pOH =14\\pOH= 14-pH = 14-12.37 = 1.63$

The $KSP$ value of $ca(oh)^{2}$ is

$ca(oh)^{2} -- > ca^{2} + (aq) +2OH^{-} \\ksp = 4s^{3}$

The value finally becomes,

$ksp = 5.15 * x=10^{-5}$

<h3>What are the properties of Saturated solution ?</h3>

A saturated solution is one that contains all of the solute that can possibly dissolve in it. The most sodium chloride that may dissolve in $100 g$ of water at $20$ °C is $36.0 g$ . Past that point, adding more $NaCl$ won't cause it to dissolve because the solution is already saturated.

The solution reaches a point when it is saturated. This indicates that if you add more of the substance, it will stop dissolving and instead stay solid. The amount depends on how the solvent and solute interact molecularly.

To learn more about saturated solution, visit

brainly.com/question/9414660

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5 0

1 year ago