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evablogger [386]
4 years ago
14

Explain how by having bright and colorful flowers help plant in reproduction

Chemistry
1 answer:
sergeinik [125]4 years ago
3 0
This attracts bees which, when collecting the nectar, they carry residue pollen on the flower to the next flower, which then pollinates the flowers, hence allowing them to asexually reproduce.
You might be interested in
A student bought a statue made up of copper. after a couple of months it acquired a dull green coating, explain the reason with
swat32
I have no formula however the process would be erosion... copper is a type of metal and when it rots from water or any type of liquid damage it erodes and gets that green coat.
4 0
3 years ago
Do you think it's possible for a renewable resource such as water to become depleted or
Naya [18.7K]
Yes if we use the resource up before it can renew itself then it could be used up and be depleted or near depletion. The resource has to have time to come back and if we use it up to fast then the resource can not take the time it needs to come back.
6 0
2 years ago
What is the formula for the stable binary ionic compound formed between Barium and Oxygen?
xeze [42]

Answer: a. BaO

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here element barium is having an oxidation state of +2 called as Ba^{2+} cation and O^{2-} is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral BaO

3 0
3 years ago
4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.
Elodia [21]

Answer:

Y=48.6\%

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

2Cu+O_2\rightarrow 2CuO

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO}  =0.078gCuO

Therefore, the percent yield is:

Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%

Best regards.

6 0
3 years ago
If your conclusion does not agree with (disproves) your hypothesis:
Nataliya [291]

If your findings disproves your hypothesis then your hypothesis is probably wrong.


5 0
3 years ago
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