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Marrrta [24]
3 years ago
13

A metal (M) forms an oxide with the formula MO. If the oxide contains 7.17 % O by mass, what is the identity of the metal?

Chemistry
1 answer:
Nataly_w [17]3 years ago
7 0

The metal is lead, Pb.

One unit of the oxide contains one atom of O (16.00 u).

∴ Mass of oxide = 16.00 u O × (100 u MO/7.17 u O) = 223.15 u MO

Mass of M = mass of MO – mass of O = 223.15 u -16.00 u = 207.2 u

The only element with an atomic mass of 207.2 u is lead (Pb) and the formula of the oxide is PbO.

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Explanation:

From the knowledge of law of multiple proportions,

mass ratio of S to O in SO:

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ratio of mass ratio of S to O in SO to mass ratio of S to O in SO2:

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Explanation:

Let's consider the following balanced equation.

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First, we have to calculate the moles of Sn²⁺ that react.

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We also know the following relations:

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Then, for 1.348 × 10⁻3 moles of Sn²⁺:

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