Question

5 A photographer runs away from an angry rhino toward the safety of her Jeep What will happen? (Speeds and distances are shown below the image.)
O
O
o
- Photographer is 10 meters from the Jeep
--Photographer runs 6 meters per second,
-Rhinois 16 meters from the Jeep
-Rhino runs 8 meters per second
- The Jeep is not moving
o
.
O A. The photographer will get to the Jeep before the rhino catches her
O B. The rhino will catch the photographer before she reaches the Jeep
O . The rhino and the photographer will reach the Jeep at the same time,
OD. More information is needed

Answer 1

Answer:

A. The photographer will get to the jeep before the rhinocerous

Explanation:

Δv =  Δd/Δt

we can rearrange for time

Δt = Δd/Δv

For the photographer:

Distance is 10m and moves at 6m/s

Δt = 10m/6m/s

Δt = 1.67s

For the rhinocerous

Distance is 16m and moves at 8m/s

Δt = 16m/8m/s

Δt = 2.00s

The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino