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faltersainse [42]
2 years ago
9

5 A photographer runs away from an angry rhino toward the safety of her Jeep What will happen? (Speeds and distances are shown b

elow the image.)
O
O
o
- Photographer is 10 meters from the Jeep
--Photographer runs 6 meters per second,
-Rhinois 16 meters from the Jeep
-Rhino runs 8 meters per second
- The Jeep is not moving
o
.
O A. The photographer will get to the Jeep before the rhino catches her
O B. The rhino will catch the photographer before she reaches the Jeep
O . The rhino and the photographer will reach the Jeep at the same time,
OD. More information is needed

Physics
1 answer:
irinina [24]2 years ago
8 0

Answer:

A. The photographer will get to the jeep before the rhinocerous

Explanation:

Δv =  Δd/Δt

we can rearrange for time

Δt = Δd/Δv

For the photographer:

Distance is 10m and moves at 6m/s

Δt = 10m/6m/s

Δt = 1.67s

For the rhinocerous

Distance is 16m and moves at 8m/s

Δt = 16m/8m/s

Δt = 2.00s

The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino

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Answer:

128 N

Explanation:

Power can be defined as

P = F\cdot v

<em>F</em> is the force and <em>v</em> is the velocity.

F = \dfrac{P}{v}

According to the question, <em>P</em> = 5.15 hp = 5.15 × 746 W.

<em>v</em> = 30 m/s

F = \dfrac{5.15\times 746\text{ W}}{30\text{ m/s}} = 128 \text{ N}

Since most of the power is used to compensate for the energy transformations due to friction forces, the total frictional is 128 N

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Would you expect to weigh more on an ocean beach or on top of a mountain? Explain.
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An Ocean beach

Explanation:

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7 0
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Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is
Zigmanuir [339]
Efficiency = 45J/120J = 0.375

Or

0.375 * 100% = 37.5 %
3 0
3 years ago
A student drew the following model:
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What is the melting point of substance A?
Misha Larkins [42]

Answer:

Solids are easily recognized by their ability to retain a fixed shape and definite volume. Particles making

up a solid are held together in a rigid form. They are not free to move about or slide past one another and

the solid does not have the ability to flow. (Although the particles of a solid do not move position to position, they do have motion in that they are constantly vibrating.

To change the temperature of a solid, heat energy must be added. The amount of heat energy that changes

the temperature of 1.0 g of a solid by 1.0°C is called its specific heat (c). Each substance has its own

specific heat. The specific heat of ice is 2.1 Joules/g°C. In other words we must supply 1.0 gram of ice

with 2.1 Joules of heat energy to raise its temperature by 1.0 °C.

The general equation for calculating heat energy to change the temperature of a solid is:

Heat = Mass x Specific Heat (solid) x Temperature Change

Q = m c DT

10 g 10 g 10 g 10 g 10 g 10 g

Calculate the heat necessary to change 10 g of ice(s) at -20 °C to 10 g of ice(s) at 0°C. (A-B)

Q = mc∆T = (10 g) (2.1 J/g°C) (20°C) = 420 J

If you continue to add heat energy once the temperature of the ice reaches 0°C , the heat absorbed is called

the heat of fusion (Lf). This heat is used to cause a change of phase (from a solid to a liquid). This heat is

increasing the potential energy of the molecules of the solid. No temperature change takes place. Each

substance has its own heat of fusion. The heat of fusion for ice is 340 Joules/g. Exactly the same amount

of heat is given up when 1.0 g of water is changed to ice. This heat is called the heat of crystallization.

The general equation for calculating heat energy to change a solid to a liquid is:

Heat = Mass x Heat of Fusion

Q = m Lf

Calculate the heat necessary to change 10 g of ice(s) at 0°C to 10 g of water(l) at 0°C.(B-C)

Explanation:

Q = mLf = (10 g)( 340 J/g) = 3400 J

3 0
3 years ago
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