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faltersainse [42]
2 years ago
9

5 A photographer runs away from an angry rhino toward the safety of her Jeep What will happen? (Speeds and distances are shown b

elow the image.)
O
O
o
- Photographer is 10 meters from the Jeep
--Photographer runs 6 meters per second,
-Rhinois 16 meters from the Jeep
-Rhino runs 8 meters per second
- The Jeep is not moving
o
.
O A. The photographer will get to the Jeep before the rhino catches her
O B. The rhino will catch the photographer before she reaches the Jeep
O . The rhino and the photographer will reach the Jeep at the same time,
OD. More information is needed

Physics
1 answer:
irinina [24]2 years ago
8 0

Answer:

A. The photographer will get to the jeep before the rhinocerous

Explanation:

Δv =  Δd/Δt

we can rearrange for time

Δt = Δd/Δv

For the photographer:

Distance is 10m and moves at 6m/s

Δt = 10m/6m/s

Δt = 1.67s

For the rhinocerous

Distance is 16m and moves at 8m/s

Δt = 16m/8m/s

Δt = 2.00s

The distances were to get to the jeep, the photographer makes it to the jeep in a shorter amount of time than the rhino

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You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
PLEASE HELP!!! WILL MARK THE BRAINLIEST! HIGH SCHOOL PHYSICAL SCIENCE List the independent, dependent, controlled variables of t
serious [3.7K]

Answer:

Explanation:

You didn't last any of the variables. You have to list the variables to tell which are which.

3 0
3 years ago
Read 2 more answers
A mother and her young child want to play on a seesaw at a playground. The child sits on the end of one side of the seesaw. Wher
EleoNora [17]

Answer:middle

Explanation:

Because it will make the seasaw balanced

4 0
3 years ago
When AC Electric is producing 120 volts with 20 amps, What controls the the 120 volts at 60cycles a second?
lubasha [3.4K]

Answer:

Cycles per second is dependent on the construction of the alternator and the 120 volts is dependent upon the current and resistance in the circuit according to the ohms law.

Explanation:

We are given with AC of 120 volts, 20 amperes and 60 hertz frequency.

<u>According to the Ohm's law, we find its resistance:</u>

R=\frac{V}{I}

R=\frac{120}{20}

R=6\ \Omega

So, this 6 ohm resistance controls the current controls the magnitude of the AC current, while the frequency of the current remains constant and depends upon the construction and rotational speed of the armature of the alternator producing the current.

Here the value of frequency is the number of times the current changes its direction or the polarity in one second.

6 0
3 years ago
One of the harmonics of a string fixed at both ends has a frequency of 52.2 Hz and the next higher harmonic has a frequency of 6
Angelina_Jolie [31]

Solution :

Frequency may be defined as the number of observation or number of waves that is taken in per unit time. The unit of frequency is Hertz or Hz.

It is given that :

Successive harmonic frequencies, f = 52.2 Hz

and f' = 60.9 Hz

Therefore, fundamental frequency, F = f' - f

                                                           F = 60.9 - 52.2

                                                          F = 8.7 Hz

Therefore the string which is fixed at both the ends forms all the harmonics.

6 0
2 years ago
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