Answer:
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Explanation:
INLOVE THE WORDS U USE THERE
Answer:hhhkkzkxixuhhhdhhdhdhhhdhhhshsbbsbzhhdhhdhhhshhhdhhdusudhggdydyydhshdhgddhsjsudhdhhdh
Explanation:NzjzjhbxxhzhdghsjshshhHjajskajakakakakaiaiaiijhayayayagayahahah
Answer:
U(0.0m) = 0J
U(5.5m) = 40.42 J
Explanation:
The gravitational potential energy is given by the following formula:

h: height
m: mass of the apple = 0.75kg
g: gravitational acceleration = 9.8m/s^2
When the apple is at 5.5m from the ground the gravitational potential energy is:

when the apple is on the ground you have:

Answer:
The coefficient of friction in the hall is 0.038
Explanation:
Given;
mass of the Parker, m = 73.2 kg
applied force on the parker, F = 123 N
frictional force, Fs = 27.4 N
the coefficient of friction in the hall = ?
frictional force is given by;
Fs = μN
Where;
μ is the coefficient of friction
N is normal reaction = mg
Fs = μmg
μ = Fs / mg
μ = (27.4) / (73.2 x 9.8)
μ = 0.038
Therefore, the coefficient of friction in the hall is 0.038